Question Video: Determining the Union of Two Mutually Exclusive Events | Nagwa Question Video: Determining the Union of Two Mutually Exclusive Events | Nagwa

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Question Video: Determining the Union of Two Mutually Exclusive Events Mathematics • Third Year of Preparatory School

A bag contains red, blue, and green balls, and one is to be selected without looking. The probability that the chosen ball is red is equal to seven times the probability that the chosen ball is blue. The probability that the chosen ball is blue is the same as the probability that the chosen ball is green. Find the probability that the chosen ball is red or green.

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Video Transcript

A bag contains red, blue, and green balls, and one is to be selected without looking. The probability that the chosen ball is red is equal to seven times the probability that the chosen ball is blue. The probability that the chosen ball is blue is the same as the probability that the chosen ball is green. Find the probability that the chosen ball is red or green.

We will begin by naming the events of choosing a red ball, a blue ball, and a green ball as R, B, and G, respectively. Since the selected ball can only be one of these three colors, we can conclude that the events are mutually exclusive. Our aim in this question is to find the probability that the chosen ball is red or green. This is the probability of the union of the two events. And we recall for any two mutually exclusive events 𝑥 and 𝑦, the probability of 𝑥 union 𝑦 is equal to the probability of 𝑥 plus the probability of 𝑦. This means that we need to find the sum of the probability that the chosen ball is red and the probability that the chosen ball is green.

We are told that the probability that the chosen ball is red is seven times the probability that the chosen ball is blue. This can be written as shown. We are also told that the probability that the chosen ball is blue is the same as the probability that the chosen ball is green.

Finally, since there are only red, blue, and green balls in the bag and these are mutually exclusive events, we have the probability of red plus the probability of blue plus the probability of green is equal to one. Replacing the probability of red and the probability of green using equations one and two, we have the following equation. Seven multiplied by the probability of blue plus the probability of blue plus the probability of blue is equal to one. This simplifies to nine multiplied by the probability of blue is equal to one. And the probability that the selected ball is blue is therefore equal to one-ninth.

This means that the probability that the chosen ball is green is also equal to one-ninth. And the probability that the chosen ball is red is seven-ninths. After clearing some space, we can now calculate the probability that the chosen ball is red or green. This is equal to seven-ninths plus one-ninth, which in turn is equal to eight-ninths. When a ball is selected from the bag without looking, the probability that the chosen ball is red or green is eight-ninths.

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