Lesson Explainer: Mutually Exclusive Events | Nagwa Lesson Explainer: Mutually Exclusive Events | Nagwa

Lesson Explainer: Mutually Exclusive Events Mathematics

In this explainer, we will learn how to identify mutually exclusive events and non-mutually exclusive events and find their probabilities.

Before we discuss mutually exclusive events, let’s recap compound events and the addition rule of probability.

Key Terms: Compound Events and the Addition Rule of Probability

The intersection of events 𝐴 and 𝐡, denoted by 𝐴∩𝐡, is the collection of all outcomes that are elements of both of the sets 𝐴 and 𝐡; this is equivalent to both events occurring.

The union of events 𝐴 and 𝐡, denoted by 𝐴βˆͺ𝐡, is the collection of all outcomes that are elements of either set 𝐴, set 𝐡, or both sets; this is equivalent to either of the events occurring.

If an event 𝐴 in a sample space 𝑆 cannot occur, then its probability is 0. Since 𝑃(𝐴)=𝑛(𝐴)𝑛(𝑆)=0, we must have 𝑛(𝐴)=0. In other words, there are no elements in 𝐴. We call the set with no elements the empty set and denote this set by βˆ….

The addition rule for probability states that 𝑃(𝐴βˆͺ𝐡)=𝑃(𝐴)+𝑃(𝐡)βˆ’π‘ƒ(𝐴∩𝐡).

We can use this as motivation for a definition. If 𝑃(𝐴∩𝐡)=0, then the addition rule for probability would simplify to 𝑃(𝐴βˆͺ𝐡)=𝑃(𝐴)+𝑃(𝐡).

We call events where 𝑃(𝐴∩𝐡)=0Β mutually exclusive events since both events cannot occur at the same time. We can write this formally as follows:

Definition: Mutually Exclusive Events and the Additive Rule for Mutually Exclusive Events

We say that 𝐴 and 𝐡 are mutually exclusive events if 𝐴∩𝐡=βˆ…. This is equivalent to saying the events cannot occur at the same time since 𝑃(𝐴∩𝐡)=𝑃(βˆ…)=0.

We say that a list of events 𝐴,𝐴,…,𝐴 is mutually exclusive if they are pairwise mutually exclusive, so 𝐴∩𝐴=βˆ…οƒο… for any 𝑖 and π‘—βˆˆ{1,2,…,𝑛}.

If 𝐴 and 𝐡 are mutually exclusive, then 𝑃(𝐴βˆͺ𝐡)=𝑃(𝐴)+𝑃(𝐡).

To see an example of mutually exclusive events, we can recall that the intersection of two events 𝐴 and 𝐡 can be shown in a Venn diagram as the part of the diagram in the overlap of 𝐴 and 𝐡. So, in a Venn diagram, mutually exclusive events have an empty intersection.

In the first diagram, there is no intersection between the events, so the events are mutually exclusive. However, in the second diagram, there is an intersection between liking cats and dogs, so the events are not mutually exclusive. Of course, even though there is an intersection, we should still check that there is at least one member in the intersection to be sure.

In our first example, we will determine whether given pairs of events are mutually exclusive.

Example 1: Deciding If Events Are Mutually Exclusive

Farida has a deck of 52 cards. She randomly selects one card and considers the following events:

Event A: picking a card that is a heart

Event B: picking a card that is black

Event C: picking a card that is not a spade

  1. Are events A and B mutually exclusive?
  2. Are events A and C mutually exclusive?
  3. Are events B and C mutually exclusive?

Answer

We start by recalling that two events 𝑋 and π‘Œ are mutually exclusive if they cannot occur at the same time. In other words, 𝑃(π‘‹βˆ©π‘Œ)=0.

Therefore, to determine if the given pairs of events are mutually exclusive, we need to check whether there are any cards from the 52-card deck that satisfy both events.

Part 1

There are two ways of checking whether the events of β€œpicking a card that is a heart” and β€œpicking a card that is black” are mutually exclusive.

First, we can note that all hearts are red, so there are no cards that are both black and a heart. Therefore, both events cannot happen, and so the events are mutually exclusive.

Second, we can mark all of the cards for each event and check whether there is any overlap in the events.

We mark all of the hearts in red (event A) and all of the black cards in green (event B). We can see that there is no overlap in these events, so they cannot occur simultaneously.

Hence, we can say that yes, the events A and B are mutually exclusive.

Part 2

As in part 1, there are two ways of checking whether the events of β€œpicking a card that is a heart” and β€œpicking a card that is not a spade” are mutually exclusive.

First, we can note that all of the hearts are not spades, so choosing any heart will satisfy both events. Then, since the events can both occur at the same time, we can conclude they are not mutually exclusive.

Second, we can mark all of the cards for each event and check whether there is any overlap in the events.

We mark the hearts with red (event A) and all of the cards that are not spades in blue (event C). We can see that all hearts satisfy both events A and C, so the events are not mutually exclusive.

Hence, we can say that no, the events A and C are not mutually exclusive.

Part 3

There are two ways of checking whether the events of β€œpicking a card that is black” and β€œpicking a card that is not a spade” are mutually exclusive.

First, we could note that all clubs are black and not a spade, so choosing any of these cards satisfies both events.

Second, we can mark all of the cards for each event and check whether there is any overlap in the events.

We mark all of the black cards with purple (event B) and all of the cards that are not spades in blue (event C). We can see that all clubs satisfy both events B and C, so the events are not mutually exclusive.

Hence, we can say that no, events B and C are not mutually exclusive.

In our second example, we will use the mutual exclusivity of two events and their probabilities to determine the probability of either event occurring.

Example 2: Determining the Probability of Union of Two Mutually Exclusive Events

Two mutually exclusive events 𝐴 and 𝐡 have probabilities 𝑃(𝐴)=110 and 𝑃(𝐡)=15. Find 𝑃(𝐴βˆͺ𝐡).

Answer

We recall that since 𝐴 and 𝐡 are mutually exclusive, 𝑃(𝐴∩𝐡)=0. Therefore, the addition rule for probability tells us that when 𝐴 and 𝐡 are mutually exclusive, 𝑃(𝐴βˆͺ𝐡)=𝑃(𝐴)+𝑃(𝐡)βˆ’π‘ƒ(𝐴∩𝐡)=𝑃(𝐴)+𝑃(𝐡).

We can then substitute 𝑃(𝐴)=110 and 𝑃(𝐡)=15 into this equation to get 𝑃(𝐴βˆͺ𝐡)=110+15=310.

In our next example, we will use the addition rule for probability on mutually exclusive events to determine the probability of either event occurring.

Example 3: Determining the Probability of an Event Using A Given relationship between Mutually Exclusive Events

Suppose that 𝐴 and 𝐡 are two mutually exclusive events. The probability of the event 𝐡 occurring is five times that of the event 𝐴 occurring. Given that the probability that one of the two events occurs is 0.18, find the probability of event 𝐴 occurring.

Answer

We know that the probability of either 𝐴 or 𝐡 occurring (𝑃(𝐴βˆͺ𝐡)) is 0.18. We know that 𝐴 and 𝐡 are mutually exclusive, and we recall that this means that 𝑃(𝐴∩𝐡)=0. We also know that the probability of 𝐡 occurring is five times that of 𝐴 occurring, so 𝑃(𝐡)=5𝑃(𝐴). We can then recall that since 𝐴 and 𝐡 are mutually exclusive, the addition rule for probability tells us 𝑃(𝐴βˆͺ𝐡)=𝑃(𝐴)+𝑃(𝐡).

Substituting 𝑃(𝐴βˆͺ𝐡)=0.18 and 𝑃(𝐡)=5𝑃(𝐴) into the formula gives 0.18=𝑃(𝐴)+5𝑃(𝐴)0.18=6𝑃(𝐴).

We can then divide the equation by 6 to get 𝑃(𝐴)=0.186=0.03.

In our next example, we will use the context of a word problem to deduce whether the given events are mutually exclusive and then use this to determine the probability of either event occurring.

Example 4: Using the Addition Rule to Determine the Probability of Union of Mutually Exclusive Events

A small choir has a tenor singer, 3 soprano singers, a baritone singer, and a mezzo-soprano singer. If one of their names was randomly chosen, determine the probability that it was the name of the tenor singer or soprano singer.

Answer

We can start by sketching the information given to get a clear idea of the composition of the choir.

If we assume that the singers stick to their parts so that, for example, a soprano singer does not sing tenor or baritone parts and vice versa, then the events of choosing a soprano, tenor, baritone, or mezzo-soprano singer are mutually exclusive, since no two events can occur at the same time.

This being the case, to find the probability that a randomly chosen singer is either a tenor or a soprano singer, we can use the probability rule 𝑃(𝐴βˆͺ𝐡)=𝑃(𝐴)+𝑃(𝐡), since, by mutual exclusivity of 𝐴 and 𝐡, 𝑃(𝐴∩𝐡)=0.

As there are 6 singers in total and only one is a tenor singer, the probability that a randomly chosen singer is a tenor singer is 𝑃()==16.tenornumberoftenorssizeofchoir

Similarly, there are 3 soprano singers; hence, 𝑃()==36=12.sopranonumberofsopranossizeofchoir

Applying the rule that says that for mutually exclusive events, 𝑃(𝐴βˆͺ𝐡)=𝑃(𝐴)+𝑃(𝐡), we have 𝑃(βˆͺ)=𝑃()+𝑃()=16+12=23.tenorsopranotenorsoprano

In our next example, we will use the mutual exclusivity of three events and properties of probability to determine the probability of a compound event occurring in a word problem.

Example 5: Determining the Union of Two Mutually Exclusive Events

A bag contains red, blue, and green balls, and one is to be selected without looking. The probability that the chosen ball is red is equal to seven times the probability that the chosen ball is blue. The probability that the chosen ball is blue is the same as the probability that the chosen ball is green.

Find the probability that the chosen ball is red or green.

Answer

We can name the events of choosing a red ball, a blue ball, and a green ball 𝑅, 𝐡, and 𝐺 respectively. Since a chosen ball can only be one of these three colors, we can conclude that the events are mutually exclusive. We want to determine the probability that the ball chosen is red or green, that is, 𝑃(𝑅βˆͺ𝐺).

The additive rule for probability tells us 𝑃(𝑅βˆͺ𝐺)=𝑃(𝑅)+𝑃(𝐺)βˆ’π‘ƒ(π‘…βˆ©πΊ).

Since the events are mutually exclusive, we know that 𝑃(π‘…βˆ©πΊ)=0, so 𝑃(𝑅βˆͺ𝐺)=𝑃(𝑅)+𝑃(𝐺).

We are told in the question that the probability that the chosen ball is red is equal to seven times the probability that the chosen ball is blue, so 𝑃(𝑅)=7𝑃(𝐡).

We are also told that the probability that the chosen ball is blue is the same as the probability that the chosen ball is green, so 𝑃(𝐡)=𝑃(𝐺).

Finally, since there are only red, blue, and green balls in the bag and these are mutually exclusive events, we have 𝑃(𝑅)+𝑃(𝐡)+𝑃(𝐺)=1.

Substituting 𝑃(𝐺)=𝑃(𝐡) and 𝑃(𝑅)=7𝑃(𝐡) into this equation gives 7𝑃(𝐡)+𝑃(𝐡)+𝑃(𝐡)=19𝑃(𝐡)=1.

Dividing the equation by 9 gives 𝑃(𝐡)=19.

Since the probability that the chosen ball is blue is the same as the probability that the chosen ball is green, we have 𝑃(𝐺)=19.

Since the probability that the chosen ball is red is equal to seven times the probability that the chosen ball is blue, we have 𝑃(𝑅)=79.

Substituting these values into the additive rule for probability for mutually exclusive events, we get 𝑃(𝑅βˆͺ𝐺)=79+19=89.

In our final example, we will note that two events are not mutually exclusive and then use the given probabilities along with the addition rule for probability to determine the probability of an event.

Example 6: Finding the Probability of a Difference of Two Events given the Probability of Each Event as well as Their Intersection

The probability that a student passes their physics exam is 0.71. The probability that they pass their mathematics exam is 0.81. The probability that they pass both exams is 0.68. What is the probability that the student only passes their mathematics exam?

Answer

To find the probability that the student passes mathematics but not physics, let’s illustrate the events in a Venn diagram. We note that since there is an overlap, the events are not mutually exclusive and can occur together. This gives us the following:

Now, if we highlight the probabilities that we know concerning the event β€œpasses math” on the diagram, that is, 𝑃()=0.81Math and 𝑃(∩)=0.68MathPhysics, we have

The event β€œpasses math” is everything inside the red oval, which has a probability of 0.81. The overlap in the center of the diagram covers β€œpasses both math and physics” and has a probability of 0.68. But we want to find the probability of passing mathematics but not physics, which covers the dark purple section in the diagram below.

Since the probability of passing math is made up of the probability of passing math but not physics and the probability of passing both, we have 𝑃()=𝑃()+𝑃(∩)0.81=𝑃()+0.68.MathMathbutnotphysicsMathPhysicsMathbutnotphysics

Rearranging this gives us 𝑃()=0.81βˆ’0.68=0.13.Mathbutnotphysics

Hence, the probability that a student passes mathematics but not physics is 0.13.

Let’s finish by recapping some of the important points from this explainer.

Key Points

  • We say that 𝐴 and 𝐡 are mutually exclusive events if 𝐴∩𝐡=βˆ…. This is equivalent to saying the events cannot occur at the same time, since 𝑃(𝐴∩𝐡)=𝑃(βˆ…)=0.
  • We say that a list of events is mutually exclusive if they are pairwise mutually exclusive.
  • If events 𝐴 and 𝐡 are mutually exclusive, then 𝑃(𝐴βˆͺ𝐡)=𝑃(𝐴)+𝑃(𝐡).
  • If events 𝐴 and 𝐡 are not mutually exclusive, then 𝑃(𝐴βˆͺ𝐡)=𝑃(𝐴)+𝑃(𝐡)βˆ’π‘ƒ(𝐴∩𝐡). where 𝑃(𝐴∩𝐡)β‰ 0

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