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Question Video: Determining the Coordinates of Points after Translation Mathematics • First Year of Preparatory School

Find the images of the points 𝐴 and 𝐵 of the line segment 𝐴𝐵 under the translation (4, 3).

02:16

Video Transcript

Find the images of the points 𝐴 and 𝐵 of the line segment 𝐴𝐵 under the translation four, three.

We’re going to carry out the translation four, three on this line segment. That means the line segment will move four units to the right and three units up. The images of these points are the points of 𝐴 and 𝐵 after the translation. A translation will add or subtract constant values from the 𝑥- and 𝑦-coordinates. A translation 𝑝, 𝑞 on the point 𝑥, 𝑦 will be mapped to 𝑥 add 𝑝, 𝑦 add 𝑞.

So let’s start by carrying out this translation graphically. We can do this by firstly considering point 𝐴 and then point 𝐵. We move point 𝐴 four units to the right and three units up. We denote this new point with 𝐴 prime. Now we can do the same with point 𝐵. We move point 𝐵 four units to the right and three units up. This gives us the image of 𝐵, 𝐵 prime. We then get the translated line segment by joining 𝐴 prime with 𝐵 prime.

We can read the images of 𝐴 and 𝐵 directly from the graph by reading the coordinates of the points 𝐴 prime and 𝐵 prime. We could also use our formal definition to work out these points. 𝐴 is the point negative two, negative six. We map 𝐴 to its image, 𝐴 prime, by adding four to the 𝑥-coordinate, because that’s the horizontal translation, and three to the 𝑦-coordinate, because that’s the vertical translation. That gives us the image 𝐴 prime is two, negative three.

Let’s calculate 𝐵 prime. Point 𝐵 has coordinates one, negative four. We map this to its image by adding four to the 𝑥-coordinate and three to the 𝑦-coordinate. That gives us the image of 𝐵, 𝐵 prime, is five, negative one. We can verify these points by checking the translation we did on the graph. And we see that the images of 𝐴 and 𝐵 are correct. So that’s our answer. The image of 𝐴 is two, negative three, and the image of 𝐵 is five, negative one.

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