### Video Transcript

Write four over π₯ plus one plus two π₯ over two π₯ plus three as a single fraction
in its simplest form.

To solve this problem, we can see that weβve actually got two algebraic fractions and
we want to add them. And as with any type of fraction, when you want to add fractions, you need to find a
common denominator. And one method we can actually use is the cross multiplication method, which allows
us to add our fractions.

So what we have is if we have two fractions π over π plus π over π, then we
multiply π by π β so we get ππ β plus π multiplied by π β so ππ. And then you multiply the two denominators β so π by π. So we get ππ. Okay, fab, so this is actually a method. Itβs gonna help us to solve our problem. So letβs get on add together our algebraic
fractions.

So we can say that four over π₯ plus one plus two π₯ over two π₯ plus three is gonna
be equal to four multiplied by two π₯ plus three plus two π₯ multiplied by π₯ plus
one cause again we cross multiplied all over π₯ plus one multiplied by two π₯ plus
three. Okay, great, so weβve now completed the first step.

So now, what weβre gonna do is actually expand the parentheses on the numerator. So weβre gonna get eight π₯ as we got four multiplied by two π₯ plus 12 because we
have four multiplied by three plus two π₯ squared cause two π₯ multiplied by π₯
gives us two π₯ squared plus two π₯ and then this is all over π₯ plus one multiplied
by two π₯ plus three.

So therefore, what we can do now is actually simplify our numerator. So we get two π₯ squared plus 10π₯ plus 12 over π₯ plus one multiplied by two π₯ plus
three. And we got that because we actually combine the like terms that we could. So we had eight π₯ plus two π₯ give us 10π₯. Okay, great, so weβve now written it as a single fraction. But is it in its simplest form?

Well, actually, I think thereβs one more step we can do because we can actually take
a factor out of our numerator. And this gives us two multiplied by π₯ squared plus five π₯ plus six because two is a
factor of each of our terms over π₯ plus one multiplied by two π₯ plus three. But is this the final answer? Well, actually, if we look at this now, we can actually see that weβve got in the
numerator a quadratic that we can actually factor. Well, letβs have a quick look at how weβre gonna do that.

So weβve got π₯ squared plus five π₯ plus six. Well, weβve got positive π₯ squared, which means that weβre gonna have an π₯ at the
beginning of each of our parentheses. Okay, so now what? Well, what we need to do is we need to find a pair of factors that multiply together
to give us positive six and add together to give us positive five. So therefore, the two numbers that weβre gonna get are positive three and positive
two because two multiplied by three gives us six and two add three gives us five or
positive five.

So great, we found our factors. Theyβre π₯ plus three multiplied by π₯ plus two. So therefore, we can say that if we write four over π₯ plus one plus two π₯ over two
π₯ plus three as a single fraction in its simplest form, itβs gonna be equal to two
multiplied by π₯ plus two π₯ plus three over π₯ plus one two π₯ plus three.