Question Video: Sketching the Graph of a Linear Relation given the Coefficients | Nagwa Question Video: Sketching the Graph of a Linear Relation given the Coefficients | Nagwa

Question Video: Sketching the Graph of a Linear Relation given the Coefficients Mathematics • Second Year of Preparatory School

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Given the relation π‘Žπ‘₯ + 𝑏𝑦 = 𝑐, sketch the graph of this relation if π‘Ž = 5, 𝑏 = 0, and 𝑐 = 1.

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Video Transcript

Given the relation π‘Žπ‘₯ plus 𝑏𝑦 equals 𝑐, sketch the graph of this relation if π‘Ž equals five, 𝑏 equals zero, and 𝑐 equals one.

To sketch the graph of the given relation, we first substitute the given values for the coefficients π‘Ž, 𝑏, and 𝑐 into the equation. This gives five times π‘₯ plus zero times 𝑦 equals one. That is, five π‘₯ equals one. And we can make π‘₯ the subject of this new equation by dividing through by five, so we have π‘₯ is equal to one-fifth.

We could look at this another way by recalling that if 𝑏 equals zero in the linear relation π‘Žπ‘₯ plus 𝑏𝑦 equals 𝑐, then π‘₯ is equal to 𝑐 over π‘Ž. And this is exactly what we found with 𝑐 equal to one and π‘Ž equal to five.

Now to sketch the graph of this relation, π‘₯ equals one-fifth, we note that this relation is interpreted as β€œFor every value of 𝑦, π‘₯ is equal to one-fifth.” The graph of this relation is therefore a vertical line through π‘₯ equals one-fifth, which we note as a decimal is 0.2. Hence, the graph of the relation π‘Žπ‘₯ plus 𝑏𝑦 equals 𝑐 with π‘Ž equals five, 𝑏 equals zero, and 𝑐 equals one is a vertical line through π‘₯ equals 0.2.

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