Video Transcript
Given the relation ππ₯ plus ππ¦ equals π, sketch the graph of this relation if π equals five, π equals zero, and π equals one.
To sketch the graph of the given relation, we first substitute the given values for the coefficients π, π, and π into the equation. This gives five times π₯ plus zero times π¦ equals one. That is, five π₯ equals one. And we can make π₯ the subject of this new equation by dividing through by five, so we have π₯ is equal to one-fifth.
We could look at this another way by recalling that if π equals zero in the linear relation ππ₯ plus ππ¦ equals π, then π₯ is equal to π over π. And this is exactly what we found with π equal to one and π equal to five.
Now to sketch the graph of this relation, π₯ equals one-fifth, we note that this relation is interpreted as βFor every value of π¦, π₯ is equal to one-fifth.β The graph of this relation is therefore a vertical line through π₯ equals one-fifth, which we note as a decimal is 0.2. Hence, the graph of the relation ππ₯ plus ππ¦ equals π with π equals five, π equals zero, and π equals one is a vertical line through π₯ equals 0.2.