Video Transcript
A car starting from rest accelerated at 1.3 meters per second squared. Determine the distance required for it to reach a velocity of 26 meters per second.
We can answer this question by using our equations of uniform acceleration, often known as the SUVAT equations. 𝑠 is the displacement, 𝑢 the initial velocity, 𝑣 the final velocity, 𝑎 the acceleration, and 𝑡 the time. In this question, we’re told that the acceleration is 1.3 meters per second squared. The car begins from rest, so the initial velocity is zero meters per second. We need to calculate the distance when the velocity is 26 meters per second. So this is our value of 𝑣.
We will use the equation 𝑣 squared is equal to 𝑢 squared plus two 𝑎𝑠. Substituting in our values, we have 26 squared is equal to zero squared plus two multiplied by 1.3 multiplied by 𝑠. 26 squared is equal to 676, and two multiplied by 1.3 is 2.6. We have 676 is equal to 2.6𝑠. Dividing both sides of this equation by 2.6 gives us 𝑠 is equal to 260.
The displacement from the start point is 260. Therefore, the distance required to reach a velocity of 26 meters per second is 260 meters.
