Question Video: Finding the Width of a Rectangle given Its Area and Length by Dividing Two Polynomials | Nagwa Question Video: Finding the Width of a Rectangle given Its Area and Length by Dividing Two Polynomials | Nagwa

Question Video: Finding the Width of a Rectangle given Its Area and Length by Dividing Two Polynomials Mathematics • First Year of Preparatory School

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What is the width of a rectangle whose area is (βˆ’π‘₯⁴ + 20π‘₯Β² + 16π‘₯) cmΒ² and whose length is (βˆ’π‘₯Β² + 4π‘₯ + 4) cm?

03:03

Video Transcript

What is the width of a rectangle whose area is negative π‘₯ to the fourth power plus 20π‘₯ squared plus 16π‘₯ square centimeters and whose length is negative π‘₯ squared plus four π‘₯ plus four centimeters?

Let’s begin by sketching a diagram of a rectangle with the given length and area. We recall that the area of a rectangle is given by the product of its length and width. This means we can determine the width of this rectangle by dividing its area by its length. In this case, we will be dividing a fourth-degree polynomial by a quadratic polynomial. We can do this by using polynomial long division. When setting up our long division, we notice that the fourth-degree polynomial does not have a cubic term or a constant. In this situation, we’ll insert a zero for each missing term. This allows us to have a column for each degree term in standard form order for our future computations.

To begin, we divide the leading term of the dividend by the leading term of the divisor to get π‘₯ squared. We add this to the quotient and then subtract π‘₯ squared times the divisor. We find the product of π‘₯ squared in the divisor is negative π‘₯ to the fourth power plus four π‘₯ cubed plus four π‘₯ squared. Then, we subtract this expression from the dividend. We must be careful to subtract each term, not just the first term. It may be helpful to first distribute the negative through the parentheses then combine like terms. This looks like adding π‘₯ to the fourth power, subtracting four π‘₯ cubed, and subtracting four π‘₯ squared. This gives us the new dividend, negative four π‘₯ cubed plus 16π‘₯ squared plus 16π‘₯.

As long as the degree of the dividend is greater than or equal to the degree of the divisor, we apply this process again. So, we start again with the leading term of the new dividend divided by the leading term of the divisor. The quotient of negative four π‘₯ cubed divided by negative π‘₯ squared is four π‘₯. So, we add four π‘₯ to the quotient. Then, we multiply four π‘₯ with the divisor. The result is negative four π‘₯ cubed plus 16π‘₯ squared plus 16π‘₯, which we need to subtract from the new dividend. At this step, we can distribute the negative sign and then combine like terms. The result is a remainder of zero. So, the quotient is π‘₯ squared plus four π‘₯.

Having taken the quotient of the area divided by the length, we found the width of the rectangle to be π‘₯ squared plus four π‘₯ centimeters.

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