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Question Video: Identifying Perpendicular Vectors Mathematics • First Year of Secondary School

Which of the following vector pairs are perpendicular? [A] 〈2, 0〉, 〈3, −6〉 [B] 〈1, 4〉, 〈2, 8〉 [C] 〈0, 7〉, 〈0, 9〉 [D] 〈3, 0〉, 〈0, 6〉

03:25

Video Transcript

Which of the following vector pairs are perpendicular? Option (A) vector two, zero and vector three, negative six. Option (B) vector one, four and vector two, eight. Option (C) vector zero, seven and vector zero, nine. Or option (D) vector three, zero and vector zero, six.

Let’s begin by recalling how we identify if vectors are perpendicular. If we have two vectors 𝐮 and 𝐯 which are perpendicular, then the dot product of vector 𝐮 and 𝐯 is equal to zero. We can remind ourselves of how to find the dot product by saying that if vector 𝐮 is given by 𝑥 one, 𝑦 one and vector 𝐯 is given by 𝑥 two, 𝑦 two, then the dot product 𝐮𝐯 is equal to 𝑥 one times 𝑥 two plus 𝑦 one times 𝑦 two. So, in each of these options, (A) to (D), we’ll work out this dot product, and if it’s equal to zero, then the vector pair will be perpendicular. So, let’s start with the vector pair given in option (A). And we can identify 𝑥 one, 𝑦 one, 𝑥 two, and 𝑦 two values, although it doesn’t matter which vector we choose for each of the 𝑥 one and 𝑦 one values.

To find the dot product then, we’ll have two times three plus zero times negative six. Evaluating this, two times three gives us six. And be careful because, of course, zero times negative six is zero. Six plus zero simplifies to six. So, did we calculate the dot product equal to zero? No, we did not. Therefore, the vector pair given in option (A) are not perpendicular. We can follow the same process then for the vectors given in option (B). When we calculate the dot product here, we have one times two plus four times eight. One times two is two, and four times eight is 32. Adding these together gives us the value of 34. As this dot product is not equal to zero, then the vectors given in option (B) are not perpendicular.

Applying the same method for the vectors given in option (C), we’re multiplying zero by zero and adding it to seven times nine, which gives us 63. 63 is not equal to zero, so the vectors in option (C) are not perpendicular. Finally, in option (D), each of the products of 𝑥 one, 𝑥 two and 𝑦 one, 𝑦 two will give us zero. So, when we add these together, we get zero. As we have found a dot product of vectors which is equal to zero, then these two vectors given in option (D) are perpendicular. Therefore, we can give the answer that vector three, zero and vector zero, six are perpendicular.

We can confirm this by drawing these two vectors. The vector three, zero could be represented by a line going three units to the right and zero units up. Vector zero, six could be represented by a line which goes zero units horizontally and six units upwards. The first vector is a horizontal line, and the second vector is a vertical line, indicating that these two vectors are indeed perpendicular and so confirming that the vector pair which is perpendicular are those given in option (D).

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