Question Video: Determining the Correctness of a Statement Involving Integers | Nagwa Question Video: Determining the Correctness of a Statement Involving Integers | Nagwa

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Question Video: Determining the Correctness of a Statement Involving Integers Mathematics • Second Year of Preparatory School

Is every noninteger number a rational number?

02:58

Video Transcript

Is every noninteger number a rational number?

In this question, we need to determine if every noninteger number is necessarily a rational number.

We can start by recalling that integers are the whole numbers. So they are the positive whole numbers, the negative whole numbers, and zero. The nonintegers will include any number that is not a whole number. We can also recall that the rational numbers is the set of quotients of integers where the denominator is nonzero. We can then answer this question by recalling that the square root of two is not an integer, and it is also not a rational number. So, the answer is no, not every noninteger number is a rational number.

Although this is enough to answer this question, we can prove that this is the case by showing that the square root of two cannot be written as the quotient of integers. To do this, let’s start by assuming that root two is a rational number. So, it can be written as 𝑎 over 𝑏, where 𝑎 and 𝑏 are integers and 𝑏 is nonzero. We can assume that the greatest common divisor of 𝑎 and 𝑏 is one, since we can cancel any common factors in the numerator and denominator.

We can now square both sides of the equation to get that two is equal to 𝑎 squared over 𝑏 squared. If we multiply through by 𝑏 squared, we can note that the left-hand side of the equation is even since it is the product of an even number and an integer. This means that the right-hand side of the equation must also be even; this can only be true if 𝑎 is even. Let’s say that 𝑎 is two times some integer 𝑐. If we substitute 𝑎 equals two 𝑐 into the equation, we obtain two 𝑏 squared equals two 𝑐 all squared. We can rewrite two 𝑐 all squared as four 𝑐 squared and then divide both sides of the equation through by two. This gives us that 𝑏 squared equals two 𝑐 squared.

We can now use the same reasoning we did before. We see that two 𝑐 squared is even. So, 𝑏 squared must also be even, meaning that 𝑏 itself is even. However, we already showed that 𝑎 and 𝑏 have a greatest common divisor of one. And we also know that neither 𝑎 or 𝑏 can be zero, so this is not possible. Hence, our original assumption that the square root of two is rational must be incorrect. So, the square root of two is an example of a noninteger that is not a rational number.

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