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Video: SAT Practice Test 1 • Section 3 • Question 6

A line in the 𝑥𝑦-plane has a slope of −2/3 and passes through the point (12, 3). What is the 𝑦-intercept of this line?

03:54

Video Transcript

A line in the 𝑥𝑦-plane has a slope of negative two-thirds and passes through the point 12, three. What is the 𝑦-intercept of this line?

To figure out what the 𝑦-intercept is for this line, we must first understand where the 𝑦-intercept is located on the equation of a line. So the equation of a line is 𝑦 equals 𝑚𝑥 plus 𝑏, where 𝑚 is the slope and 𝑏 is the 𝑦-intercept, where it crosses the 𝑦-axis. So for this line, we will be looking for 𝑏.

So in this question, we’re given two things. We’re given the slope, also known as 𝑚, is negative two-thirds. And it passes through the point 12, three. So there’s two routes we could take to solve this question.

Looking at the equation of a line, we have 𝑦 equals 𝑚𝑥 plus 𝑏. So we could plug in negative two-thirds for 𝑚 and then 𝑥 and 𝑦, 12 and three. And then all that would be left for us to find would be 𝑏, the 𝑦-intercept.

The other route would be using the point slope formula. When you’re given a point that a line goes through and its slope, there’s a formula that we can use to find the exact equation of the line. And once we have the equation of the line, we could find the 𝑦-intercept.

Let’s use this first method and then go through the second method using the point slope formula. So plugging in these values, we will have three equals negative two-thirds times 12 plus 𝑏. And we can solve for 𝑏. So we need to take negative two-thirds times 12. Well, three goes into 12 four times. And then we can take four times negative two to be negative eight. And then to solve for 𝑏, we take three plus eight to give us 11.

So the 𝑦-intercept is where this line crosses the 𝑦-axis. So if we were to draw this line on the 𝑥𝑦-plane, we would cross the 𝑦-axis at 11, which would be here. And this is the point zero, 11. So the 𝑦-intercept would be the point zero, 11.

Now just take a closer look at this graph. Once we’ve plotted the 𝑦-intercept, we used the slope to get the rest of the points that are on the line. And the slope is negative two-thirds. So it’s the rise over the run, so the vertical change over the horizontal change. So if we have negative two-thirds from this point at zero, 11, we should go down two and right three. So we will be around here.

Two points is enough to make a line. However, let’s do one more, which will be somewhere around here. We will actually need this sixth spot on the 𝑥-axis. But here we would have our line.

So now let’s solve for the 𝑦-intercept using the other method, the point slope formula. 𝑦 minus 𝑦 one equals 𝑚 times 𝑥 minus 𝑥 one, where 𝑚 is the slope, so negative two-thirds, and 𝑥 one, 𝑦 one is the point that the line goes through, so 12, three. So plugging these values in, we will simplify and then we will have the equation of the line. So we should get 𝑦 equals negative two-thirds 𝑥 plus 11, because we found the 𝑦-intercept to be 11.

So first, let’s distribute the negative two-thirds. So we take negative two-thirds times 𝑥, which is negative two-thirds 𝑥, and negative two-thirds times negative 12. Three goes into 12 four times. So negative two times negative four — be careful not to miss that negative — would give us positive eight.

And now our last step to get it in the form of 𝑦 equals 𝑚𝑥 plus 𝑏, the equation of a line, we add three to both sides of the equation. And just as we said, we get 𝑦 equals negative two-thirds 𝑥 plus 11, where negative two-thirds is the slope and 11 is the 𝑦-intercept.

So once again, to answer our question, the 𝑦-intercept of this line would be the point zero, 11.

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