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In this lesson, we will learn how to use the slope-intercept form of two-variable linear equations to find the slope and the y-intercept of their line.

Q1:

Calculate the gradient and the -intercept for the function .

Q2:

Find the slope π and the π¦ -intercept π of this straight line.

Q3:

True or false: The equation of a line passing through the origin is π¦ = π π₯ .

Q4:

Which of the following graphs represents the equation π¦ = 4 π₯ β 1 ?

Q5:

Which of the following graphs represents the equation π¦ = π₯ + 3 ?

Q6:

Write the equation that represents the linear function shown in the given table.

Q7:

What is the π¦ -intercept of the line passing through ( β 2 , β 1 6 ) and ( 1 , β 4 ) ?

Q8:

Write a linear function in the form π¦ = π π₯ + π , that has a slope of 3 and a π¦ -intercept of 8.

Q9:

True or false: The equation of a line intercepting the vertical axis at π is π¦ = π π₯ + π .

Q10:

What is the relation between the point ( 0 , 4 ) and the line π¦ = 2 π₯ β 8 ?

Q11:

A straight line is defined by the equation π¦ = π π₯ + π .

Given that the point ( π₯ , π¦ ) 1 1 lies on the line, find an expression for π in terms of π , π₯ 1 , and π¦ 1 .

Given also that the point ( π₯ , π¦ ) 2 2 lies on the line and π is the slope of the line, find an expression for π in terms of π¦ 1 , π¦ 2 , π₯ 1 , and π₯ 2 .

By substituting in for π and factorizing out π , find the formula for the equation of the line.

Substitute in your expression for π to complete your formula.

Q12:

The general form for the equation of any linear function is π¦ = π π₯ + π . What do π and π represent?

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