Question Video: Identifying Which Species Are Oxidized or Reduced in a Chemical Equation | Nagwa Question Video: Identifying Which Species Are Oxidized or Reduced in a Chemical Equation | Nagwa

Question Video: Identifying Which Species Are Oxidized or Reduced in a Chemical Equation Chemistry • Third Year of Secondary School

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Consider the following reaction: Cl₂ (aq) + 2KI (aq) ⟶ I₂ (aq) + 2KCl (aq) Which of the following statements is correct? [A] Iodide ions are oxidized and gain electrons. [B] Iodide ions are oxidized and lose electrons. [C] Chlorine is reduced and loses electrons. [D] Potassium ions are oxidized and lose electrons. [E] Potassium iodide is oxidized and gains electrons.

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Video Transcript

Consider the following reaction: Cl2 aqueous and two KI aqueous react to form I2 aqueous and two KCl aqueous. Which of the following statements is correct? (A) Iodide ions are oxidized and gain electrons. (B) Iodide ions are oxidized and lose electrons. (C) Chlorine is reduced and loses electrons. (D) Potassium ions are oxidized and lose electrons. (E) Potassium iodide is oxidized and gains electrons.

In this question, we need to identify which statement correctly describes the reaction of chlorine and potassium iodide. Let’s first define some of the terms found in the answer options. When a chemical species is oxidized, we say it undergoes oxidation. Oxidation is a type of chemical reaction where a chemical species loses electrons. When a chemical species is reduced, we say it undergoes reduction. Reduction is a type of reaction where a chemical species gains electrons. We can remember these terms by the acronym OIL RIG. Oxidation is the loss of electrons, and reduction is the gain of electrons.

To get some practice, we will first look at an example of a reaction that undergoes oxidation and reduction, and then we will look at the equation given to us in the question.

In this example, solid calcium metal reacts with gaseous diatomic oxygen molecules. Solid calcium oxide is formed. Both reactants are in their elemental form. They are neither oxidized nor reduced. They have not lost nor gained electrons. The calcium oxide product consists of two ions. It consists of the positively charged calcium two plus ion. Positive ions are also called cations. And it consists of the negatively charged oxide two minus ion. A negatively charged ion is called an anion.

When calcium metal atoms are converted to calcium two plus cations, each atom loses two electrons. This is oxidation. When oxygen atoms are transformed into oxide two minus anions, they each gain two electrons. This is reduction.

Now that we have practiced identifying substances which are oxidized and reduced, let’s have a look at the equation in the question.

Here is the chemical equation. Let’s show the charges for the substances which consist of ions. Potassium iodide consists of K+ cations and I− anions. And potassium chloride consists of K+ cations and Cl− anions. We can see that each atom of elemental chlorine, which is neither oxidized nor reduced, gains one electron and so is reduced. Notice that potassium ions are unchanged. They do not gain electrons, nor do they lose electrons. They remain as K+ cations. And each iodide ion, I−, in the reactants loses one electron as it is transformed to elemental iodine, which is not charged. Elemental iodine is neutral. So iodide ions are oxidized.

We can see that the only answer option which correctly describes the processes shown in the equation is answer (B). Iodide ions are oxidized and lose electrons.

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