Lesson Explainer: The Domain and the Range of a Radical Function | Nagwa Lesson Explainer: The Domain and the Range of a Radical Function | Nagwa

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Lesson Explainer: The Domain and the Range of a Radical Function Mathematics • Second Year of Secondary School

In this explainer, we will learn how to find the domain and the range of a radical function either from its graph or from its defining rule.

In particular, we will focus on the domain and range of functions involving the square and the cube roots.

Let us begin by recalling the definitions of domain and range of a function.

Theorem: Domain and Range of a Function

The domain of a function ๐‘“(๐‘ฅ) is a set of all possible values ๐‘ฅ such that the expression ๐‘“(๐‘ฅ) is defined.

The range of a function ๐‘“(๐‘ฅ) is a set of all possible values the expression ๐‘“(๐‘ฅ) can take, when ๐‘ฅ is any number from the domain of the function.

For example, consider the function ๐‘“(๐‘ฅ)=โˆš๐‘ฅ. If there is a real number ๐‘ฆ satisfying ๐‘ฆ=โˆš๐‘ฅ, it must be the case that ๐‘ฅ=๐‘ฆ๏Šจ. We know that the square of any real number is not negative; thus ๐‘ฅ must be nonnegative. This tells us that the domain of the square root function is ๐‘ฅโ‰ฅ0, which is expressed in the interval notation as [0,โˆž[.

The graph of the square root function is shown below.

In the figure above, the square root function is graphed over the interval [0,2]. Although the graph of the function appears to become flatter for larger values of ๐‘ฅ, it continues to increase without a bound. We can observe this effect by graphing the square root function over a larger interval, [0,1000].

We can see that the ๐‘ฆ-value of the graph keeps increasing for larger values of ๐‘ฅ. In fact, given any large positive number ๐‘ฆ, we know that โˆš๐‘ฆ=๐‘ฆ๏Šจ. Also, we know that โˆš0=0. Hence, the range of the square root function is [0,โˆž[.

Theorem: Domain and Range of the Square Root Function

The domain and range of the square root function, ๐‘“(๐‘ฅ)=โˆš๐‘ฅ, is [0,โˆž[.

More generally, the domain of a composite square root function โˆš๐‘”(๐‘ฅ) can be identified by finding the values of ๐‘ฅ satisfying ๐‘”(๐‘ฅ)โ‰ฅ0.

Let us consider a few examples where we identify the domain and the range of functions involving the square root.

Example 1: Finding the Domain of Root Functions

Consider the function ๐‘“(๐‘ฅ)=โˆšโˆ’๐‘ฅ.

  1. Find the domain of ๐‘“(๐‘ฅ).
  2. Find the range of ๐‘“(๐‘ฅ).

Answer

Part 1

We recall that the square root cannot take a negative number as an argument. Hence, the domain of the given function is found by setting the expression inside the square root to be greater than or equal to zero. In other words, โˆ’๐‘ฅโ‰ฅ0.

This leads to ๐‘ฅโ‰ค0, which is ]โˆ’โˆž,0] in interval notation.

The domain of ๐‘“(๐‘ฅ) is ]โˆ’โˆž,0].

Part 2

The range of a function is the set of all possible function values. We know that the range of the square root function โˆš๐‘ฅ is [0,โˆž[. In other words, for any number ๐‘ฆ in the interval [0,โˆž[, we can find some number ๐‘ฅ that satisfies ๐‘ฆ=โˆš๐‘ฅ. This means that the number โˆ’๐‘ฅ satisfies ๐‘“(โˆ’๐‘ฅ)=โˆšโˆ’(โˆ’๐‘ฅ)=โˆš๐‘ฅ=๐‘ฆ.

Hence, any number in the interval [0,โˆž[ is a possible function value of ๐‘“(๐‘ฅ)=โˆšโˆ’๐‘ฅ.

The range of ๐‘“(๐‘ฅ) is [0,โˆž[.

Let us consider another example for obtaining the domain of a composite square root function.

Example 2: Finding the Domain of Root Functions

Find the domain of the function ๐‘“(๐‘ฅ)=โˆš7๐‘ฅโˆ’7.

Answer

Recall that the domain of a function โˆš๐‘”(๐‘ฅ) is the set of ๐‘ฅ-values satisfying ๐‘”(๐‘ฅ)โ‰ฅ0.

In this example, ๐‘”(๐‘ฅ)=7๐‘ฅโˆ’7. Hence, the domain of this function is the set of ๐‘ฅ-values such that 7๐‘ฅโˆ’7โ‰ฅ0.

Rearranging this inequality leads to ๐‘ฅโ‰ฅ1, which is written as [1,โˆž[ in interval notation.

The domain of ๐‘“(๐‘ฅ)=โˆš7๐‘ฅโˆ’7 is [1,โˆž[.

In the next example, we will determine the correct graph of a composite square root function by considering its domain and range.

Example 3: Identifying the Graph of a Radical Function

Which of the following is the graph of ๐‘“(๐‘ฅ)=โˆš1โˆ’2๐‘ฅ?

Answer

Let us use the domain and the range of ๐‘“(๐‘ฅ)=โˆš1โˆ’2๐‘ฅ to identify the graph. We know that the domain of โˆš๐‘”(๐‘ฅ) is the set of ๐‘ฅ-values satisfying ๐‘”(๐‘ฅ)โ‰ฅ0.

In this example, ๐‘”(๐‘ฅ)=1โˆ’2๐‘ฅ. Hence, the domain of this function is the set of ๐‘ฅ-values such that 1โˆ’2๐‘ฅโ‰ฅ0.

Rearranging this inequality leads to ๐‘ฅโ‰ค12, which is written as ๏ โˆ’โˆž,12๏  in interval notation. Hence, the domain of ๐‘“(๐‘ฅ) is ๏ โˆ’โˆž,12๏ .

Recall that the range of the square root function โˆš๐‘ฅ is [0,โˆž[. We have observed that ๐‘“(๐‘ฅ)=โˆš๐‘”(๐‘ฅ) where ๐‘”(๐‘ฅ)=1โˆ’2๐‘ฅ. Since the range of ๐‘”(๐‘ฅ)=1โˆ’2๐‘ฅ is all real numbers, โˆš๐‘”(๐‘ฅ) must have the same range as โˆš๐‘ฅ. This leads to the range of ๐‘“(๐‘ฅ), which is [0,โˆž[.

Let us identify which one of the graphs represents a function whose domain is ๏ โˆ’โˆž,12๏  and whose range is [0,โˆž[. From each given graph, the domain of the function corresponding to the graph is the part of the horizontal axis where the graph exists. Also, the range of the function is the part of the vertical axis where the graph exists. We obtain the domain and range of each function using its graph.

  1. Domain: ๏”12,โˆž๏”, range: [0,โˆž[
  2. Domain: ๏ โˆ’โˆž,12๏ , range: ]โˆ’โˆž,0[
  3. Domain: ]โˆ’โˆž,โˆž[, range: ]โˆ’โˆž,โˆž[
  4. Domain: ๏ โˆ’โˆž,12๏ , range: [0,โˆž[
  5. Domain: ๏”โˆ’12,โˆž๏”, range: [0,โˆž[

Therefore, the only possible match for ๐‘“(๐‘ฅ)=โˆš1โˆ’2๐‘ฅ is D.

We might recall that when working with rational functions, we must be careful to restrict the domain to ensure that the function on the denominator of the expression cannot be equal to zero. Let us demonstrate how to find the domain of a function which is a ratio of two composite square root functions.

Example 4: Finding the Domain of Rational Functions

Determine the domain of the function ๐‘“(๐‘ฅ)=โˆš๐‘ฅ+7โˆš๐‘ฅโˆ’5.

Answer

In the given function, we observe two types of restrictions to the domain.

  • Square root: there are two expressions โˆš๐‘ฅ+7 and โˆš๐‘ฅโˆ’5. We recall that the square root function cannot take a negative number.
  • Denominator: this is the expression โˆš๐‘ฅโˆ’5. We recall that the denominator of a fraction cannot equal zero.

We begin by considering the restrictions imposed by the square roots. For โˆš๐‘ฅ+7 to be well defined, we need ๐‘ฅ+7โ‰ฅ0. This leads to ๐‘ฅโ‰ฅโˆ’7, which is the interval [โˆ’7,โˆž[.

For โˆš๐‘ฅโˆ’5 to be well defined, we need ๐‘ฅโˆ’5โ‰ฅ0, which leads to ๐‘ฅโ‰ฅ5, or [5,โˆž[.

Finally, let us consider the denominator. Since the denominator cannot equal zero, we need to exclude the case when โˆš๐‘ฅโˆ’5=0. Squaring both sides of this equation gives ๐‘ฅโˆ’5=0, leading to ๐‘ฅ=5. Hence, we need to impose ๐‘ฅโ‰ 5.

The domain of this function is the set of ๐‘ฅ-values satisfying all three conditions: [โˆ’7,โˆž[,[5,โˆž[,๐‘ฅโ‰ 5.

To see how these three restrictions interact, let us draw a number line with these restrictions.

In the diagram above, the purple highlight represents the interval [โˆ’7,โˆž[, the green highlight represents the interval [5,โˆž[, and the red X represents the restriction ๐‘ฅโ‰ 5. We can draw an interval that satisfies the intersection of these restrictions simultaneously.

Hence, the domain of ๐‘“(๐‘ฅ) is ]5,โˆž[.

Example 5: Finding the Domain of Rational Functions

Find the domain of ๐‘“(๐‘ฅ)=โˆš๐‘ฅโˆ’1โˆš9โˆ’๐‘ฅโˆ’โˆš๐‘ฅโˆ’3.

Answer

In the given function, we observe two types of restrictions to the domain.

  • Square root: there are the three expressions โˆš๐‘ฅโˆ’1, โˆš9โˆ’๐‘ฅ, and โˆš๐‘ฅโˆ’3. We recall that the square root function cannot take a negative number.
  • Denominator: this is the expression โˆš9โˆ’๐‘ฅโˆ’โˆš๐‘ฅโˆ’3. We recall that the denominator of a fraction cannot equal zero.

We begin by considering the restrictions imposed by the square roots. For โˆš๐‘ฅโˆ’1 to be well defined, we need ๐‘ฅโˆ’1โ‰ฅ0. This leads to ๐‘ฅโ‰ฅ1, which is the interval [1,โˆž[.

Similarly, the expressions โˆš9โˆ’๐‘ฅ and โˆš๐‘ฅโˆ’3 lead to the intervals ]โˆ’โˆž,9] and [3,โˆž[ respectively.

Next, let us consider the denominator. Since the denominator cannot be equal to zero, we need to exclude the case when โˆš9โˆ’๐‘ฅโˆ’โˆš๐‘ฅโˆ’3=0.

We can add โˆš๐‘ฅโˆ’3 to both sides of this equation to obtain โˆš9โˆ’๐‘ฅ=โˆš๐‘ฅโˆ’3.

Squaring both sides leads to 9โˆ’๐‘ฅ=๐‘ฅโˆ’312=2๐‘ฅ๐‘ฅ=6.

Hence, we need to impose ๐‘ฅโ‰ 6.

We have found four domain restrictions for ๐‘“(๐‘ฅ): [1,โˆž[,]โˆ’โˆž,9],[3,โˆž[,๐‘ฅโ‰ 6.

Let us draw a number line to visualize how these restrictions interact.

In the diagram above, the purple highlight represents the interval [1,โˆž[, the green highlight represents the interval ]โˆ’โˆž,9], the blue highlight represents [3,โˆž[, and the red X represents the restriction ๐‘ฅโ‰ 6. We can draw the set satisfying all four restrictions simultaneously.

Hence, the domain of ๐‘“(๐‘ฅ) is [3,9]โˆ’{6}.

In previous examples, we consider the domain and range of square root functions with linear expressions, ๐‘Ž๐‘ฅ+๐‘. In the next example, we will find the domain and the range of a composite square root function where the expression inside the square root involves the absolute value function.

Example 6: Finding the Domain of Rational Functions

Consider the function ๐‘“(๐‘ฅ)=โˆš4โˆ’|๐‘ฅโˆ’5|.

  1. Find the domain of ๐‘“(๐‘ฅ).
  2. Find the range of ๐‘“(๐‘ฅ).

Answer

Part 1

Let us find the domain of the given function. We know that the domain of โˆš๐‘”(๐‘ฅ) is the set of ๐‘ฅ-values satisfying ๐‘”(๐‘ฅ)โ‰ฅ0.

In the function ๐‘“(๐‘ฅ), the expression 4โˆ’|๐‘ฅโˆ’5| is under the square root. Hence, we need to find the values of ๐‘ฅ such that 4โˆ’|๐‘ฅโˆ’5|โ‰ฅ0.

To solve an inequality with an absolute value, we begin by isolating the absolute value on one side of the inequality. Adding |๐‘ฅโˆ’5| to both sides of the inequality, we obtain 4โ‰ฅ|๐‘ฅโˆ’5|.

We can consider this in two separate situations. First, consider the case that ๐‘ฅโˆ’5 is nonnegative. Since the absolute value does not change a nonnegative number, the inequality is the same as 4โ‰ฅ๐‘ฅโˆ’5.

Second, consider the case when ๐‘ฅโˆ’5 is negative. Since the absolute value takes away a negative sign, ๐‘ฅโˆ’5 needs to be at least โˆ’4 to satisfy the inequality 4โ‰ฅ|๐‘ฅโˆ’5|. In other words, ๐‘ฅโˆ’5โ‰ฅโˆ’4. Together, 4โ‰ฅ|๐‘ฅโˆ’5| is the same as โˆ’4โ‰ค๐‘ฅโˆ’5โ‰ค4.

Adding 5 to the inequality leads to 1โ‰ค๐‘ฅโ‰ค9.

The domain of ๐‘“(๐‘ฅ) is [1,9].

Part 2

Let us find the range of ๐‘“(๐‘ฅ). The range of a function is the set of all possible values of the function. We can obtain the range of a function by considering what are the largest and the smallest possible values of the function. Since any function value ๐‘“(๐‘ฅ) is a square root of a number, we know that it cannot be negative. Thus, 0 would be the smallest possible function value if it is possible. For this, we need the expression under the square root to be equal to zero. This leads to 4=|๐‘ฅโˆ’5|.

This is possible when ๐‘ฅ=1 or ๐‘ฅ=9. This means that the smallest possible value of ๐‘“(๐‘ฅ) is 0.

To find the largest possible value of ๐‘“(๐‘ฅ), we note that |๐‘ฅโˆ’5| is a nonnegative number. Since the expression inside the square root is 4โˆ’|๐‘ฅโˆ’5|, the function would have the largest value when |๐‘ฅโˆ’5|=0, which happens when ๐‘ฅ=5. In this case, the function value is โˆš4=2. So, the largest possible value of ๐‘“(๐‘ฅ) is 2.

To finally conclude that the range of this function is [0,2], we need to know that all values between 0 and 2 are possible. If ๐‘ฆ is any value between 0 and 2, let us find a number ๐‘ฅ such that ๐‘“(๐‘ฅ)=๐‘ฆ. We have ๐‘ฆ=โˆš4โˆ’|๐‘ฅโˆ’5|.

Squaring both sides of the equation, ๐‘ฆ=4โˆ’|๐‘ฅโˆ’5|.๏Šจ

Rearranging the equation, |๐‘ฅโˆ’5|=4โˆ’๐‘ฆ.๏Šจ

As we have done previously, we can split this equation into the two cases, depending on the sign of ๐‘ฅโˆ’5. But, since we just need to find one possible value ๐‘ฅ, let us just take ๐‘ฅโˆ’5>0. In this case, we have ๐‘ฅโˆ’5=4โˆ’๐‘ฆ,๏Šจ which leads to ๐‘ฅ=9โˆ’๐‘ฆ๏Šจ. Let us check if ๐‘“๏€น9โˆ’๐‘ฆ๏…=๐‘ฆ๏Šจ. Substituting ๐‘ฅ=9โˆ’๐‘ฆ๏Šจ into the function ๐‘“(๐‘ฅ), we obtain ๐‘“๏€น9โˆ’๐‘ฆ๏…=โˆš4โˆ’|(9โˆ’๐‘ฆ)โˆ’5|=โˆš4โˆ’|4โˆ’๐‘ฆ|.๏Šจ๏Šจ๏Šจ

Since 0โ‰ค๐‘ฆโ‰ค2, we know that 4โˆ’๐‘ฆ>0๏Šจ, so we can ignore the absolute value in ||4โˆ’๐‘ฆ||๏Šจ. Continuing from above: =โˆš4โˆ’(4โˆ’๐‘ฆ)=โˆš4โˆ’4+๐‘ฆ=โˆš๐‘ฆ.๏Šจ๏Šจ๏Šจ

Since ๐‘ฆ>0, โˆš๐‘ฆ=๐‘ฆ๏Šจ. Hence, we have shown that, for any 0โ‰ค๐‘ฆโ‰ค2, we have ๐‘ฅ=9โˆ’๐‘ฆ๏Šจ that satisfies ๐‘“(๐‘ฅ)=๐‘ฆ.

The range of ๐‘“(๐‘ฅ) is [0,2].

We have considered many examples on domain and range of functions involving the square root. Unlike the square root, the cube root function does not impose any restrictions on the domain or the range. Following is the graph of the cube root function, ๏Žขโˆš๐‘ฅ.

Unlike the square root function, we note that the function extends to the left and the right side of the ๐‘ฆ-axis, indicating that the cube root can take any real numbers. We also note that the ๐‘ฆ-values tend to positive or negative infinity as we move to the left or the right. This indicates that the range of the cube root function is all real numbers.

Theorem: Domain and Range of the Cube Root Function

The domain and range of the cube root function, ๐‘“(๐‘ฅ)=โˆš๐‘ฅ๏Žข, are all real numbers. This is denoted as ]โˆ’โˆž,โˆž[ or โ„.

In the next example, we will identify the domain of a cube root function where the expression under the cube root is linear, ๐‘Ž๐‘ฅ+๐‘.

Example 7: Finding the Domain of a Cubic Root Function

Determine the domain of the function ๐‘“(๐‘ฅ)=โˆš4๐‘ฅ+3๏Žข.

Answer

Recall that the domain and the range of the cube root function ๏Žขโˆš๐‘ฅ is ]โˆ’โˆž,โˆž[. In other words, the cube root function does not impose any domain restriction. Since the expression, 4๐‘ฅ+3, under the cube root does not have any domain restriction, there are no restrictions to possible ๐‘ฅ-values for this function.

Hence, the domain of ๐‘“(๐‘ฅ)=โˆš4๐‘ฅ+3๏Žข is all real numbers, โ„.

In our final example, we will find the domain and the range of a function that involves both the square and the cube roots.

Example 8: Finding the Domain of Rational Functions

Consider the function ๐‘“(๐‘ฅ)=๏„125โˆ’โˆš2๐‘ฅ+3๏Žข.

  1. Find the domain of ๐‘“(๐‘ฅ).
  2. Find the range of ๐‘“(๐‘ฅ).

Answer

Part 1

Let us find the domain of ๐‘“(๐‘ฅ). We recall the domain restrictions for the square and the cube roots.

  • The square root function, โˆš๐‘ฅ, has the domain [0,โˆž[.
  • The cube root function, ๏Žขโˆš๐‘ฅ, has no domain restrictions. The domain of the cube root function is all real numbers, or โ„.

Since the cube root does not impose any domain restriction, we only need to consider the restriction from the square root expression โˆš2๐‘ฅ+3. Setting the expression 2๐‘ฅ+3 to be nonnegative, 2๐‘ฅ+3โ‰ฅ0.

Rearranging this inequality leads to ๐‘ฅโ‰ฅโˆ’1.5.

The domain of ๐‘“(๐‘ฅ) is [โˆ’1.5,โˆž[.

Part 2

Let us find the range of ๐‘“(๐‘ฅ). First, consider the expression โˆš2๐‘ฅ+3. Recall that the range of the square root function โˆš๐‘ฅ is [0,โˆž[. Note that โˆš2๐‘ฅ+3 can be written as โˆš2๐‘ฅ+3=๐‘”(2๐‘ฅ+3),๐‘”(๐‘ฅ)=โˆš๐‘ฅ.where

Since the range of 2๐‘ฅ+3 is all real numbers, the range of โˆš2๐‘ฅ+3 must be the same as the range of ๐‘”(๐‘ฅ). Thus, the range of โˆš2๐‘ฅ+3 is [0,โˆž[. This tells us that the expression โˆš2๐‘ฅ+3 will output nonnegative values. Then, possible values for ๐‘“(๐‘ฅ)=๏„125โˆ’โˆš2๐‘ฅ+3๏Žข can be written as ๏Žขโˆš125โˆ’๐‘Ž,๐‘Žโ‰ฅ0.forsome

The largest possible value of this happens when ๐‘Ž=0, which gives us ๏Žขโˆš125=5. Since the largest function value is 5 and we know that the cube root function, ๏Žขโˆš๐‘ฅ, tends to โˆ’โˆž to the left of ๐‘ฆ-axis, we would like to conclude that the range of the function is ]โˆ’โˆž,5]. Let us carefully justify this conclusion.

If ๐‘ฆ is some number satisfying ๐‘ฆโ‰ค5, we need to show that ๐‘ฆ=โˆš125โˆ’๐‘Ž๐‘Žโ‰ฅ0.๏Žขforsome

We can raise both sides of the equation to the cubic power to obtain ๐‘ฆ=125โˆ’๐‘Ž.๏Šฉ

Rearranging this equation leads to ๐‘Ž=125โˆ’๐‘ฆ.๏Šฉ

Since ๐‘ฆโ‰ค5, we have ๐‘ฆโ‰ค125๏Šฉ, which means ๐‘Žโ‰ฅ0. This tells us that ๐‘ฆ is a possible value of the function as long as ๐‘ฆโ‰ค5.

The range of ๐‘“(๐‘ฅ) is ]โˆ’โˆž,5].

Let us finish by recapping a few important concepts from this explainer.

Key Points

  • The domain and range of the square root function ๐‘“(๐‘ฅ)=โˆš๐‘ฅ is [0,โˆž[.
    More generally, the domain of a composite square root function โˆš๐‘”(๐‘ฅ) can be identified by finding the values of ๐‘ฅ satisfying ๐‘”(๐‘ฅ)โ‰ฅ0.
  • The domain and range of the cube root function, ๐‘“(๐‘ฅ)=โˆš๐‘ฅ๏Žข, are all real numbers. This is denoted as ]โˆ’โˆž,โˆž[ or โ„.
  • If the range of the function ๐‘”(๐‘ฅ) is all real numbers, then the range of โˆš๐‘”(๐‘ฅ) or ๏Žขโˆš๐‘”(๐‘ฅ) is [0,โˆž[ or โ„ respectively.

ุงู†ุถู… ุฅู„ู‰ ู†ุฌูˆู‰ ูƒู„ุงุณูŠุฒ

ุดุงุฑูƒ ููŠ ุงู„ุญุตุต ุงู„ู…ุจุงุดุฑุฉ ุนู„ู‰ ู†ุฌูˆู‰ ูƒู„ุงุณูŠุฒ ูˆุญู‚ู‚ ุงู„ุชู…ูŠุฒ ุงู„ุฏุฑุงุณูŠ ุจุฅุฑุดุงุฏ ูˆุชูˆุฌูŠู‡ ู…ู† ู…ุฏุฑุณ ุฎุจูŠุฑ!

  • ุญุตุต ุชูุงุนู„ูŠุฉ
  • ุฏุฑุฏุดุฉ ูˆุฑุณุงุฆู„
  • ุฃุณุฆู„ุฉ ุงู…ุชุญุงู†ุงุช ูˆุงู‚ุนูŠุฉ

ุชุณุชุฎุฏู… «ู†ุฌูˆู‰» ู…ู„ูุงุช ุชุนุฑูŠู ุงู„ุงุฑุชุจุงุท ู„ุถู…ุงู† ุญุตูˆู„ูƒ ุนู„ู‰ ุฃูุถู„ ุชุฌุฑุจุฉ ุนู„ู‰ ู…ูˆู‚ุนู†ุง. ุงุนุฑู ุงู„ู…ุฒูŠุฏ ุนู† ุณูŠุงุณุฉ ุงู„ุฎุตูˆุตูŠุฉ