Question Video: Simplifying the Quotient of a Polynomial and a Monomial | Nagwa Question Video: Simplifying the Quotient of a Polynomial and a Monomial | Nagwa

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Question Video: Simplifying the Quotient of a Polynomial and a Monomial Mathematics • First Year of Preparatory School

Simplify (4𝑥⁷𝑦³ − 6𝑥⁷𝑦⁷)/2𝑥⁵

02:20

Video Transcript

Simplify four 𝑥 to the seventh power times 𝑦 cubed minus six 𝑥 to the seventh power times 𝑦 to the seventh power all over two 𝑥 to the fifth power.

In this question, we are given an expression that we need to simplify. We can start by analyzing the expression we are given to see that it is the quotient of a polynomial and a monomial. We can divide monomials by using the quotient rule for exponents. So, we can evaluate this expression if we can rewrite it in terms of the quotient of monomials. To do this, we recall that we can split the division of the numerator over each term separately.

However, we do need to be careful since we have a difference in the numerator. So we will need to include this difference in the terms when we split the division. Dividing each term in the numerator separately by the denominator yields four 𝑥 to the seventh power 𝑦 cubed over two 𝑥 to the fifth power minus six 𝑥 to the seventh power 𝑦 to the seventh power over two 𝑥 to the fifth power.

We can now simplify each term separately by dividing the like terms and applying the quotient rule that states that we can divide two exponential expressions with the same base by subtracting their powers. Let’s apply this process to each term individually. In the first term, we can divide the coefficients to get four over two. Then we can divide the 𝑥-terms by using the quotient rule. This gives us 𝑥 to the power of seven minus five. Finally, we need to multiply this by 𝑦 cubed.

We can follow the same process for the second term. The quotient of the coefficients is six over two. We then divide the 𝑥-terms to get 𝑥 to the power of seven minus five. And then we multiply this by the 𝑦-term, 𝑦 to the seventh power. We can then evaluate the coefficients and the exponents to obtain the expression two 𝑥 squared 𝑦 cubed minus three 𝑥 squared 𝑦 to the seventh power.

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