Question Video: Determining How a Change in Temperature Affects the Equilibrium Position | Nagwa Question Video: Determining How a Change in Temperature Affects the Equilibrium Position | Nagwa

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Question Video: Determining How a Change in Temperature Affects the Equilibrium Position Chemistry • Third Year of Secondary School

NO₂ is a brown gas that can exist in equilibrium with colorless dinitrogen tetroxide, as shown in the following reaction: 2NO₂ (g) ⇌ N₂O₄ (g); Δ𝐻 = −57.2 kJ/mol. Is the enthalpy change of the forward reaction exothermic or endothermic? Which ampoule in the picture is at the highest temperature?

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Video Transcript

NO2 is a brown gas that can exist in equilibrium with colorless dinitrogen tetroxide, as shown in the following reaction. Two NO2 gas is in equilibrium with N2O4 gas. Δ𝐻 equals negative 57.2 kilojoules per mole. Is the enthalpy change of the forward reaction exothermic or endothermic? Which ampoule in the picture is at the highest temperature? (A) The forward reaction is exothermic, and the ampoule on the left is the hottest. (B) The forward reaction is exothermic, and the ampoule on the right is the hottest. (C) The forward reaction is endothermic, and the ampoule on the left is the hottest. (D) The forward reaction is endothermic, and the ampoule on the right is the hottest.

There are two parts to this problem, so let’s focus on the first question. Enthalpy change represented by Δ𝐻 is the change in the internal energy of a system. A negative enthalpy change indicates that there is a net release of energy over the course of the reaction. This type of reaction is exothermic. A positive enthalpy change indicates that there is a net increase in the energy of the system. This type of reaction is endothermic. We can see in the question that we’ve been provided with the enthalpy change. When Δ𝐻 is written after an equilibrium reaction, it indicates the change in enthalpy for the forward reaction. As this value is negative, we know that the forward reaction is exothermic. With this information, we can eliminate answer choices (C) and (D).

Now we can focus on the second question. In this question, we want to know which of the ampoules shown is at the highest temperature. To answer this question, we need to consider Le Chatelier’s principle. Le Chatelier’s principle states that for a dynamic equilibrium if the conditions change, the equilibrium position will move to counteract the change. So, if the temperature is increased, the equilibrium position will move to decrease the temperature. We know that the forward reaction is exothermic and energy is released, typically in the form of heat. The reverse reaction is the exact opposite. It is endothermic, meaning that energy, typically heat, is absorbed.

When the temperature is increased, the system will counteract the change by absorbing the added heat. Thus, the reverse reaction is favored and the equilibrium shifts towards the reactants. So, as the temperature increases, the concentration of nitrogen dioxide will increase and the concentration of dinitrogen tetroxide will decrease. We are told in the question that nitrogen dioxide is a brown gas, while dinitrogen tetroxide is colorless. If the concentration of NO2 increases as temperature increases, then the color of the ampoule should get increasingly more brown with rising temperature. So, the ampoule on the right must be the hottest.

In conclusion, with regards to the equilibrium between nitrogen dioxide and dinitrogen tetroxide, the forward reaction is exothermic and the ampoule on the right is the hottest, answer choice (B).

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