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Question Video: Finding the Maximum Speed of a Moving Parachute Mathematics • Third Year of Secondary School

A soldier jumped out of a plane with a parachute. After he had opened his parachute, the resistance to his movement was directly proportional to the cube of his speed. When his speed was 19 km/h, the resistance to his motion was 1/27 of the combined weight of him and his parachute. Determine the maximum speed of his descent.

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Video Transcript

A soldier jumped out of a plane with a parachute. After he had opened his parachute, the resistance to his movement was directly proportional to the cube of his speed. When his speed was 19 kilometers per hour, the resistance to his motion was a twenty-seventh of the combined weight of him and his parachute. Determine the maximum speed of his descent.

Let’s sketch a little diagram. Here is our soldier plummeting through the sky. The downwards force of his weight is what’s causing him to do so. Then, we have a resistance to the motion of the parachute, that’s 𝑅. And it acts in the opposite direction. We’re told that the resistance is directly proportional to the cube of his speed. So, let’s let his speed be equal to 𝑣, and that’s kilometers per hour. For this to be the case, 𝑅 must be equal to 𝑘 times 𝑣 cubed, where 𝑘 is known as the constant of proportionality. Let’s find an expression for 𝑘 by using the rest of the information in this question.

When his speed was 19, the resistance was a twenty-seventh of the combined weight of him and his parachute. So, when 𝑣 is 19, 𝑅 is one twenty-seventh times 𝑤. So, we can say that one twenty-seventh times 𝑤 is 𝑘 times 19 cubed. This means 𝑘 is a twenty-seventh 𝑤 divided by 19 cubed. Now, that’s equivalent to saying 𝑤 over 27 times 19 cubed. Now, we’re not going to work this out and we’ll see why in a moment. We can, therefore, substitute this back into our earlier equation and say 𝑅 is 𝑤𝑣 cubed over 27 times 19 cubed.

Now, we’re told that at some point the soldier reaches a maximum speed. At this point, the speed will remain unchanged. Now, for the velocity to remain uniform, Newton’s first law of motion says that the sum of all of the forces in this direction must be equal to zero. Now, let’s take downwards to be the positive direction. We can say that the weight minus the reaction force is the sum of these forces. So, 𝑤 minus 𝑅 is equal to zero. Then, adding 𝑅 to both sides, we get 𝑤 is equal to 𝑅.

But let’s replace 𝑅 with the earlier expression in terms of 𝑤 and 𝑣. And since 𝑤 is not equal to zero, we’re able to divide both sides of this equation by 𝑤. So, one is 𝑣 cubed over 27 times 19 cubed. We’re then going to multiply both sides by 27 times 19 cubed. And finally, we’re going to find the cube root of both sides. The cube root of 27 is three, and the cube root of 19 cubed is 19. So, we find three times 19 is equal to 𝑣, but three times 19 is 57. So, 𝑣 is equal to 57 and that’s kilometers per hour.

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