Video Transcript
Consider the shown trapezoid. Write an expanded expression for
its area. Simplify the expression, if
possible.
Thereβs also a second part of the
question that weβll come on to. So what weβre looking at here in
this question is the area of our trapezoid. So we need to know a formula for
this. Well, we know the formula for the
area of a trapezoid. And that is the area is equal to a
half π plus π multiplied by β. And this is where π and π are the
parallel sides of our trapezoid and β is the distance between them.
So in our trapezoid, we got π, π,
and β, which Iβve labeled. It doesnβt matter which one, the
top or the bottom, is π or π. These are interchangeable. So when we put it together, weβre
gonna get π is equal to a half multiplied by π minus five plus π plus three
multiplied by π minus four, which is gonna give us a half multiplied by two π
minus two multiplied by π minus four. So what we could do here is we
could distribute across the parentheses and then half the result. But what Iβm gonna start with is by
halfing the first parentheses. And then weβre gonna distribute
across our parentheses.
So when I do that, Iβm gonna get π
minus one multiplied by π minus four. Well, if we check what the question
wants, the question wants us to expand the expression and then simplify it. So first of all, weβre gonna expand
or weβre going to distribute across our parentheses. And when we do this, what weβre
gonna get is π multiplied by π, which is π squared. π multiplied by negative four is
negative four π. Negative one multiplied by π is
negative π. And negative one multiplied by
negative four, which is positive four.
So now, if we collect our like
terms, what weβre gonna be left with is π squared minus five π plus four since
this is our expanded expression for the area of our trapezoid. So now what weβre gonna do is weβre
gonna move on to the second part of the question.
So for the second part of the
question, weβre told that the given trapezoid is a cross section of the given prism
of length two π minus five. What we need to do is write an
expanded expression for the volume of the prism, then simplify the expression, if
possible.
Well, we have the formula for the
prism. And that formula is that the volume
is equal to the cross-sectional area or the area of the cross section multiplied by
the length. Well, we know that the area of the
cross section is equal to π squared minus five π plus four cause weβve found that
in the first part of the question. And weβre told in the second part
of the question that the length is equal to two π minus five. So therefore, we know the volume is
gonna be equal to π squared minus five π plus four multiplied by two π minus
five.
Now if we distribute across our
parentheses, first of all, weβre gonna have π squared multiplied by two π, which
is two π cubed, and π squared multiplied by negative five, which is negative five
π squared. So then weβre gonna get negative
10π squared plus 25π. Then finally, weβre gonna get
positive eight π minus 20.
Okay, now what we need to do is
simplify the expression. And we do that by collecting our
like terms. So then when weβve done that, we
get that the volume is equal to two π cubed minus 15π squared plus 33π minus
20. So there weβve found the area of
the cross section and the volume, and weβve simplified them to these two
expressions.