Question Video: Addition and Subtraction of Algebraic Expressions | Nagwa Question Video: Addition and Subtraction of Algebraic Expressions | Nagwa

Question Video: Addition and Subtraction of Algebraic Expressions Mathematics • First Year of Preparatory School

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The perimeter of a triangle is (−4𝑥⁴𝑦⁵ + 9𝑥²𝑦 − 3𝑥⁵𝑦²) cm and the lengths of two of its sides are (−5𝑥⁴𝑦⁵ − 6𝑥²𝑦) cm and (2𝑥²𝑦 + 4𝑥⁵𝑦²) cm. Express the length of the third side in terms of 𝑥 and 𝑦.

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Video Transcript

The perimeter of a triangle is negative four 𝑥 to the fourth power 𝑦 to the fifth power plus nine 𝑥 squared 𝑦 minus three 𝑥 to the fifth power 𝑦 squared centimeters. And the lengths of two of its sides are negative five 𝑥 to the fourth power 𝑦 to the fifth power minus six 𝑥 squared 𝑦 centimeters and two 𝑥 squared 𝑦 plus four 𝑥 to the fifth power 𝑦 squared centimeters. Express the length of the third side in terms of 𝑥 and 𝑦.

We begin by recalling that the perimeter of a triangle can be calculated by finding the sum of its three side lengths. In this question, we are given expressions for the lengths of two of the sides of the triangle in terms of the variables 𝑥 and 𝑦. And we are also given an expression for the perimeter of the triangle in terms of these two variables. We are asked to find an expression for the length of a third side, which we will call 𝑠.

Using this information, we can write the following equation, where the sum of the three side lengths is equal to the perimeter. Next, we can remove the parentheses and collect the like terms on the left-hand side. Recalling that like terms must have the same variables raised to the same powers, we can see that there is one such pair on the left-hand side of our equation. Negative six 𝑥 squared 𝑦 plus two 𝑥 squared 𝑦 is equal to negative four 𝑥 squared 𝑦. And as such the left-hand side simplifies to 𝑠 minus five 𝑥 to the fourth power 𝑦 to the fifth power minus four 𝑥 squared 𝑦 plus four 𝑥 to the fifth power 𝑦 squared.

Next, to isolate 𝑠, we need to add five 𝑥 to the fourth power 𝑦 to the fifth power and four 𝑥 squared 𝑦 to both sides, as well as subtracting four 𝑥 to the fifth power 𝑦 squared from both sides. This gives us 𝑠 is equal to negative four 𝑥 to the fourth power 𝑦 to the fifth power plus nine 𝑥 squared 𝑦 minus three 𝑥 to the fifth power 𝑦 squared plus five 𝑥 to the fourth power 𝑦 to the fifth power plus four 𝑥 squared 𝑦 minus four 𝑥 to the fifth power 𝑦 squared.

We are now in a position to collect like terms on the right-hand side. We recall that like terms have the same variables raised to the same powers. There are three such pairs in this case, underlined in orange, pink, and green. Firstly, we have two terms containing 𝑥 to the fourth power and 𝑦 to the fifth power. Negative four 𝑥 to the fourth power 𝑦 to the fifth power plus five 𝑥 to the fourth power 𝑦 to the fifth power is equal to 𝑥 to the fourth power 𝑦 to the fifth power. Secondly, there are two terms containing 𝑥 squared 𝑦. Nine 𝑥 squared 𝑦 plus four 𝑥 squared 𝑦 is equal to 13𝑥 squared 𝑦.

Finally, there are two terms containing 𝑥 to the fifth power 𝑦 squared. And negative three 𝑥 to the fifth power 𝑦 squared minus four 𝑥 to the fifth power 𝑦 squared is equal to negative seven 𝑥 to the fifth power 𝑦 squared. So 𝑠 is equal to 𝑥 to the fourth power 𝑦 to the fifth power plus 13𝑥 squared 𝑦 minus seven 𝑥 to the fifth power 𝑦 squared.

We can therefore conclude that the length of the third side of the triangle in terms of 𝑥 and 𝑦 is 𝑥 to the fourth power 𝑦 to the fifth power plus 13𝑥 squared 𝑦 minus seven 𝑥 to the fifth power 𝑦 squared centimeters.

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