Question Video: Determining the Charge Flowing through a Television | Nagwa Question Video: Determining the Charge Flowing through a Television | Nagwa

Reward Points

You earn points by engaging in sessions or answering questions. These points will give you a discount next time you pay for a class.

Question Video: Determining the Charge Flowing through a Television Physics • Third Year of Secondary School

A television works at an electric current of 0.5 A. If the television is turned on for 1.5 hours, then the electric charge that passes through it is _ C.

03:10

Video Transcript

A television works at an electric current of 0.5 amperes. If the television is turned on for 1.5 hours, then the electric charge that passes through it is blank coulombs. (A) 10800, (B) 5400, (C) 2700, (D) 450.

Here, we are told that a television works at an electric current of 0.5 amperes. We are also told that the television is turned on for 1.5 hours. And we are asked to figure out how much electric charge passes through it during that time.

We can solve this problem using the equation to define electric current. So let’s recall what that equation is. The current through a point is equal to the total charge that flows through the point divided by the time it takes for that charge to flow. We can write this symbolically as 𝐼, the current, is equal to 𝑄, the charge, divided by 𝑡, the time. We have values for the current and time, and we want to find the charge that flowed through the television in that time. This means that we need to rearrange the equation to make 𝑄 the subject. We can do this by multiplying both sides by the time 𝑡. Canceling the 𝑡’s on the right-hand side, we have that 𝑄 is equal to 𝐼 multiplied by 𝑡.

Before we substitute in our values for the time and current, let’s consider the units of these quantities. The current 𝐼 is given in units of amperes, which is the standard SI unit for current. However, the value we are given for the time 𝑡 is in units of hours. We need to convert this into a value in units of seconds before we can use it in the equation we found. There are 60 minutes in one hour. So, to convert from hours to minutes, we multiply by a factor of 60. Then, there are 60 seconds in one minute. So, to convert from minutes to seconds, we multiply by another factor of 60. Completing the calculation, we find that the time of 1.5 hours is equal to 5400 seconds.

We can now substitute our values for the current 𝐼 and the time 𝑡 into our equation for the charge 𝑄. We find that the total electric charge that flows through the television is equal to 0.5 amperes multiplied by 5400 seconds. On the right-hand side, we can note that the units of amperes are equivalent to units of coulombs per second. Replacing the amperes by coulombs per second, we see that the units of seconds and per second then cancel each other out. This leaves us with units of coulombs. This is a good sign. We can recognize coulombs as a valid unit of charge and the unit that is used in the question text.

Let’s now evaluate this expression. We have that the total electric charge 𝑄 is equal to 0.5 multiplied by 5400 in units of coulombs. Multiplying these values, we find that 𝑄 is equal to 2700 coulombs. That is, we have worked out that 2700 coulombs of electric charge passed through the television. This matches the value given in option (C). Therefore, the correct answer is option (C), 2700.

Join Nagwa Classes

Attend live sessions on Nagwa Classes to boost your learning with guidance and advice from an expert teacher!

  • Interactive Sessions
  • Chat & Messaging
  • Realistic Exam Questions

Nagwa uses cookies to ensure you get the best experience on our website. Learn more about our Privacy Policy