Video: Interpreting and Comparing Data Collected from a Scatterplot | Nagwa Video: Interpreting and Comparing Data Collected from a Scatterplot | Nagwa

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Video: Interpreting and Comparing Data Collected from a Scatterplot

The given scatterplot shows the print speed and cost per newspaper for 19 newspaper companies and the line of best fit for the data. The line of best fit for the data is given by the equation 𝑐 = −2.44𝑠 + 39.2, where 𝑐 is the cost in cents per newspaper and 𝑠 is the printing speed in tens of newspapers per minute. What is the best estimate for the speed, in newspapers per minute, of a company that prints 8 newspapers per dollar?

04:45

Video Transcript

The given scatter plot shows the print speed and cost per newspaper for 19 newspaper companies and the line of best fit for the data. The line of best fit for the data is given by the equation 𝑐 equals negative 2.44𝑠 plus 39.2, where 𝑐 is the cost in cents per newspaper and 𝑠 is the printing speed in tens of newspapers per minute. What is the best estimate for the speed, in newspapers per minute, of a company that prints eight newspapers per dollar?

This question is not difficult but does require us to pay close attention to units. We’re given the line of best fit 𝑐 equals negative 2.44𝑠 plus 39.2, where 𝑐 represents cents per newspaper. That means 𝑐 will be the cost in cents for every one newspaper printed. We know the company we’re interested in prints eight newspapers for every dollar. We know that one dollar is 100 cents and that with 100 cents, this company can print eight newspapers. In order for us to use this as a 𝑐 value, we need to find out if it costs 100 cents to make eight newspapers, How many cents does it cost to make one?

Eight divided by eight equals one. And if we divide the denominator by eight, we must divide the numerator by eight. 100 divided by eight equals 12 and a half. That means that it costs 12 and a half cents per newspaper printed at this company. And we can plug in 12 and a half cents per newspaper as the 𝑐 value in the line of best fit, where we’ll say 12 and a half is equal to negative 2.44𝑠 plus 39.2. To find out the speed in newspapers per minute, we’ll first need to calculate the 𝑠 value. To do that, we subtract 39.2 from both sides of the equation. 12 and a half minus 39.2 equals negative 26.7. Negative. 26.7 is equal to negative 2.44 times 𝑠.

To find 𝑠, we need to divide both sides of the equation by negative 2.44. Negative 26.7 divided by negative 2.44 equals positive 10.9426 continuing. And so we found 𝑠 equals 10.9426 continuing. But again, we need to be very careful of our units because 𝑠 is the printing speed in tens of newspapers per minute. And our question is looking for the speed in newspapers per minute, not tens of newspapers per minute. If we round 10.9426 to the nearest tenth, we get 10.9. We need to consider what 10.9 tens of newspapers per minute would be in newspapers per minute. If we have 10.9 tens, that means 10.9 times 10. And so we could say we have 109 newspapers per minute.

Now, this is not the only way we could have solved this question. If we go back to when we found 12.5 cents per newspaper, we could have then looked on our chart at 12.5 cents per newspaper. Cents per newspaper is the 𝑦-axis. If we look at 12.5 along the 𝑦-axis, we see that this is between 10 and 12 along the 𝑥-axis. And the 𝑥-axis is the print speed in tens of newspapers. If we estimate the coordinates of this point to be 11, 12 and a half, then we would say that there are 11 tens of newspapers per minute printed. And 11 tens would be equal to 110. 11 times 10 is 110. And the best estimate for that would be 109 newspapers per minute.

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