Question Video: Simplifying Exponential Expressions Using Laws of Exponents | Nagwa Question Video: Simplifying Exponential Expressions Using Laws of Exponents | Nagwa

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Question Video: Simplifying Exponential Expressions Using Laws of Exponents Mathematics • First Year of Preparatory School

Which of the following expressions has the same value as (((𝑎/𝑏)³ × (𝑎/𝑏)⁹)/(𝑎/𝑏)⁸)⁵? [A] (𝑎/𝑏)⁴ [B] (𝑎/𝑏)⁵ [C] ((𝑎/𝑏)³)⁴ [D] ((𝑎/𝑏)³)⁵ [E] ((𝑎/𝑏)⁵)⁴

04:10

Video Transcript

Which of the following expressions has the same value as 𝑎 over 𝑏 cubed multiplied by 𝑎 over 𝑏 to the ninth power over 𝑎 over 𝑏 to the eighth power all raised to the fifth power? (A) 𝑎 over 𝑏 to the fourth power. (B) 𝑎 over 𝑏 to the fifth power. (C) 𝑎 over 𝑏 to the third power to the fourth power. (D) 𝑎 over 𝑏 to the third power to the fifth power. (E) 𝑎 over 𝑏 to the fifth power to the fourth power.

We’ve been asked which of five expressions is equivalent to a given expression. Looking more closely at this expression, we can see that it is an exponential expression involving three powers of the same base, 𝑎 over 𝑏. Each of the answer options also involves the same base but is in a simplified form. To answer this question, we’ll need to simplify this expression using laws of exponents.

In the numerator of the quotient, we have the product of two powers of this base. We can recall that the product rule for exponents states that when we multiply powers of the same base together, we add the powers. So our first step is to combine the terms in the numerator by applying this rule to give 𝑎 over 𝑏 to the power of three plus nine, which simplifies to 𝑎 over 𝑏 to the 12th power.

Next, we note that we are now dividing one power of the base by another. We can therefore recall another law of exponents, which states that when dividing two powers of the same nonzero base, we subtract the powers. Applying this law gives 𝑎 over 𝑏 to the power of 12 minus eight, and this is then raised to the fifth power. Simplifying the exponent inside the parentheses gives 𝑎 over 𝑏 to the fourth power to the fifth power. Finally, we observe that we now have one power of the base raised to another power.

We can recall one final law of exponents, which is that if we raise a base to a power and then to another power, overall the base is raised to the product of those powers. Applying this law gives 𝑎 over 𝑏 to the power of four multiplied by five, which is 𝑎 over 𝑏 to the 20th power.

We’ve now fully simplified this expression, and we need to determine which of the five options it is equivalent to. At first glance, it may appear that it isn’t actually equivalent to any of the five options, as 𝑎 over 𝑏 to the 20th power isn’t listed. However, if we look at the final option, we can see that this is very similar to the penultimate stage of our working out. But the exponents of four and five have swapped places. If we apply the final law of exponents we wrote down to option (E), the expression would become 𝑎 over 𝑏 to the power of five multiplied by four. But as multiplication is commutative, five multiplied by four is the same as four multiplied by five. So in both cases, the final power evaluates to 20.

This is actually illustrative of another rule of exponents, which is that if we raise a base to a power and then to another power, that’s equivalent to raising the base to the same powers in the opposite order, because in both cases the result is the base raised to the product of those powers.

So the correct answer is option (E). The expression that is equivalent to the original expression is 𝑎 over 𝑏 to the fifth power to the fourth power.

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