Lesson Explainer: Dividing Polynomials by Monomials | Nagwa Lesson Explainer: Dividing Polynomials by Monomials | Nagwa

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Lesson Explainer: Dividing Polynomials by Monomials Mathematics • First Year of Preparatory School

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In this explainer, we will learn how to divide polynomials by monomials.

Before looking at an example where we divide a polynomial by a monomial, we need to recap some key rules and concepts.

Definition: Monomial

A monomial is an expression that contains a single term composed of a product of constants and variables with nonnegative integer exponents. The following are examples of monomials:

  • ๐‘ฅ๐‘ฆ๏Šจ
  • 3๐‘ฅ๐‘ฆ๏Šซ
  • โˆ’6๐‘Ž๐‘๐‘๏Šซ
  • ๐‘˜

Definition: Polynomial

A polynomial is an expression that contains one monomial or more. The following are examples of polynomials:

  • ๐‘ฅ+5๐‘ฅ+2๏Šจ
  • 5๐‘ฅ๐‘ฆ+๐‘ฆ๐‘ง๏Šจ
  • 12๐‘Ž๐‘+๐‘๐‘+๐‘๐‘‘+๐‘‘+10๏Šฉ

Note that monomials, and therefore polynomials, do not contain variables raised to negative exponents. For the purpose of this explainer, we also need to recap the quotient rule of exponents.

Rule: Quotient Rule

For the quotient of two exponential expressions with the same base, we have that ๐‘ฅรท๐‘ฅ=๐‘ฅ๏Œบ๏Œป๏Œบ๏Šฑ๏Œป or, equivalently, ๐‘ฅ๐‘ฅ=๐‘ฅ.๏Œบ๏Œป๏Œบ๏Šฑ๏Œป

The scope of this explainer is to cover cases of the quotient rule where ๐‘Žโ‰ฅ๐‘.

Let us now look at the process of dividing a polynomial by a monomial. For example, consider the expression 3๐‘ฅ+๐‘ฅ๐‘ฅ.๏Šจ

In this case, the polynomial and monomial are both expressed in terms of a single variable, ๐‘ฅ.

First, note that we can convert this expression into two rational expressions that consist of a monomial divided by a monomial: 3๐‘ฅ๐‘ฅ+๐‘ฅ๐‘ฅ.๏Šจ

Then, we simplify the variables using the quotient rule of exponents, which gives us 3๐‘ฅ+๐‘ฅ.(๏Šจ๏Šฑ๏Šง)(๏Šง๏Šฑ๏Šง)

This simplifies to 3๐‘ฅ+๐‘ฅ.๏Šง๏Šฆ

Now, recall that any nonzero variable raised to the power of zero is equal to 1, so ๐‘ฅ=1๏Šฆ, and any variable raised to the power of 1 is the variable itself, so ๐‘ฅ=๐‘ฅ๏Šง. Therefore, our expression simplifies to 3๐‘ฅ+1.

Another way to think of this intuitively is by considering the common factors on the top and bottom of our quotients. Note that 3๐‘ฅ๏Šจ can be expressed as 3ร—๐‘ฅร—๐‘ฅ; hence, returning to our original expression, we get 3ร—๐‘ฅร—๐‘ฅ๐‘ฅ+๐‘ฅ๐‘ฅ.

We can now cancel the common factor of ๐‘ฅ on the top and bottom of each quotient: 3ร—๐‘ฅร—๐‘ฅ๐‘ฅ+๐‘ฅ๐‘ฅ.

Clearly, by using this method, we reach the same answer as before.

Let us now look at an example.

Example 1: Dividing a Single-Variable Polynomial by a Single-Variable Monomial

Simplify ๐‘ฅ+7๐‘ฅโˆ’9๐‘ฅ๐‘ฅ๏Šช๏Šฉ๏Šจ๏Šจ.

Answer

To find the quotient, we need to divide the dividend (the top expression) by the divisor (the bottom expression). Here, both the dividend and divisor are expressed in terms of a single variable, ๐‘ฅ.

First, we convert the given expression into three rational expressions by dividing each term in the polynomial by ๐‘ฅ๏Šจ as follows: ๐‘ฅ๐‘ฅ+7๐‘ฅ๐‘ฅโˆ’9๐‘ฅ๐‘ฅ.๏Šช๏Šจ๏Šฉ๏Šจ๏Šจ๏Šจ

Next, we simplify the variables using the quotient rule, which gives us ๐‘ฅ+7๐‘ฅโˆ’9๐‘ฅ.(๏Šช๏Šฑ๏Šจ)(๏Šฉ๏Šฑ๏Šจ)(๏Šจ๏Šฑ๏Šจ)

This simplifies to ๐‘ฅ+7๐‘ฅโˆ’9๐‘ฅ.๏Šจ๏Šง๏Šฆ

Since ๐‘ฅ=1๏Šฆ and ๐‘ฅ=๐‘ฅ๏Šง, our final answer can be simplified to ๐‘ฅ+7๐‘ฅโˆ’9.๏Šจ

We will also meet quotient expressions involving multiple variables. In the simplest cases, we have a multivariable numerator and a single-variable denominator. For example, consider the expression 3๐‘ฅ๐‘ฆ+๐‘ฅ๐‘ฅ.๏Šจ๏Šจ

The numerator is expressed in terms of two variables, ๐‘ฅ and ๐‘ฆ, whereas the denominator involves just ๐‘ฅ. We can convert the given expression into two rational expressions by dividing each term in the polynomial by the monomial ๐‘ฅ: 3๐‘ฅ๐‘ฆ๐‘ฅ+๐‘ฅ๐‘ฅ.๏Šจ๏Šจ

Then, we simplify the two terms using the quotient rule of exponents. Note that, in cases like this, the ๐‘ฆ variables are undisturbed by the division operation. Therefore, we get 3๐‘ฅ๐‘ฆ+๐‘ฅ,(๏Šจ๏Šฑ๏Šง)๏Šจ(๏Šง๏Šฑ๏Šง) which simplifies to 3๐‘ฅ๐‘ฆ+1.๏Šจ

Clearly, this answer takes a very similar form to the one obtained for a single variable in the first example.

Let us now try an example of this type.

Example 2: Dividing a Multivariable Polynomial by a Single-Variable Monomial

Simplify 4๐‘ฅ๐‘ฆโˆ’6๐‘ฅ๐‘ฆ2๐‘ฅ๏Šญ๏Šฉ๏Šซ๏Šญ๏Šซ.

Answer

To find the quotient, we need to divide the dividend (the top expression) by the divisor (the bottom expression). In this case, the dividend is expressed in terms of two variables, ๐‘ฅ and ๐‘ฆ, while the divisor is expressed only in terms of ๐‘ฅ.

First, we convert the given expression into two rational expressions by dividing each term in the polynomial by the monomial 2๐‘ฅ๏Šซ: 4๐‘ฅ๐‘ฆ2๐‘ฅโˆ’6๐‘ฅ๐‘ฆ2๐‘ฅ.๏Šญ๏Šฉ๏Šซ๏Šซ๏Šญ๏Šซ

We can then simplify each of the constants: 4๐‘ฅ๐‘ฆ2๐‘ฅโˆ’6๐‘ฅ๐‘ฆ2๐‘ฅ.๏Šจ๏Šญ๏Šฉ๏Šซ๏Šฉ๏Šซ๏Šญ๏Šซ

This leaves us with 2๐‘ฅ๐‘ฆ๐‘ฅโˆ’3๐‘ฅ๐‘ฆ๐‘ฅ.๏Šญ๏Šฉ๏Šซ๏Šซ๏Šญ๏Šซ

Next, we simplify the variables by applying the quotient rule, giving us 2๐‘ฅ๐‘ฆโˆ’3๐‘ฅ๐‘ฆ,(๏Šญ๏Šฑ๏Šซ)๏Šฉ(๏Šซ๏Šฑ๏Šซ)๏Šญ which further simplifies to 2๐‘ฅ๐‘ฆโˆ’3๐‘ฅ๐‘ฆ.๏Šจ๏Šฉ๏Šฆ๏Šญ

Since ๐‘ฅ=1๏Šฆ, we get 2๐‘ฅ๐‘ฆโˆ’3๐‘ฆ๏Šจ๏Šฉ๏Šญ, and this is our final answer.

Other quotient expressions involve multiple variables in both the numerator and denominator, including ones where the divisor monomial has a coefficient greater than 1. However, we can still follow the same method, as long as we remember to simplify the constants as well as the variables. For example, consider the more complex expression 4๐‘ฅ๐‘ฆ+8๐‘ฅ๐‘ฆโˆ’2๐‘ฅ๐‘ฆ2๐‘ฅ๐‘ฆ.๏Šจ๏Šฉ

In this case, the polynomial and monomial are both expressed in terms of two variables, ๐‘ฅ and ๐‘ฆ. This time, we convert the given expression into three rational expressions by dividing each term in the polynomial by the monomial 2๐‘ฅ๐‘ฆ: 4๐‘ฅ๐‘ฆ2๐‘ฅ๐‘ฆ+8๐‘ฅ๐‘ฆ2๐‘ฅ๐‘ฆโˆ’2๐‘ฅ๐‘ฆ2๐‘ฅ๐‘ฆ.๏Šจ๏Šฉ

We can then simplify each of the constants: 4๐‘ฅ๐‘ฆ2๐‘ฅ๐‘ฆ+8๐‘ฅ๐‘ฆ2๐‘ฅ๐‘ฆโˆ’2๐‘ฅ๐‘ฆ2๐‘ฅ๐‘ฆ.๏Šจ๏Šจ๏Šช๏Šฉ

This leaves us with 2๐‘ฅ๐‘ฆ๐‘ฅ๐‘ฆ+4๐‘ฅ๐‘ฆ๐‘ฅ๐‘ฆโˆ’๐‘ฅ๐‘ฆ๐‘ฅ๐‘ฆ.๏Šจ๏Šฉ

We can now simplify the variables using the quotient rule of exponents; we get 2๐‘ฅ๐‘ฆ+4๐‘ฅ๐‘ฆโˆ’๐‘ฅ๐‘ฆ.(๏Šจ๏Šฑ๏Šง)(๏Šง๏Šฑ๏Šง)(๏Šง๏Šฑ๏Šง)(๏Šง๏Šฑ๏Šง)(๏Šง๏Šฑ๏Šง)(๏Šฉ๏Šฑ๏Šง)

This simplifies to 2๐‘ฅ๐‘ฆ+4๐‘ฅ๐‘ฆโˆ’๐‘ฅ๐‘ฆ.๏Šง๏Šฆ๏Šฆ๏Šฆ๏Šฆ๏Šจ

Again, recall that any nonzero variable raised to the power of zero is equal to 1 and any variable raised to the power of 1 is the variable itself, which means that our expression can be further simplified to 2๐‘ฅ+4โˆ’๐‘ฆ.๏Šจ

In reality, rather than explicitly quoting the quotient rule of exponents, it is perfectly acceptable to simplify the expression by canceling from the top and the bottom. For example, once we separated the expression into individual rational expressions, we could have shown our working as follows: 4๐‘ฅ2๐‘ฆ2๐‘ฅ๐‘ฆ+8๐‘ฅ๐‘ฆ2๐‘ฅ๐‘ฆโˆ’2๐‘ฅ๐‘ฆ32๐‘ฅ๐‘ฆ.๏Šจ๏Šง๏Šช๏Šจ

Although this might seem very busy, by looking carefully, we can see that we are left with 2๐‘ฅ+4โˆ’๐‘ฆ.๏Šจ

In cases of a multivariable denominator, it may seem easier to simplify one variable at a time; let us see an example of this now.

Example 3: Dividing a Multivariable Polynomial by a Multivariable Monomial

Find the quotient of 26๐‘Ž๐‘โˆ’9๐‘Ž๐‘๐‘Ž๐‘๏Šญ๏Šซ๏Šฉ๏Šซ๏Šจ.

Answer

To find the quotient, we need to divide the dividend (the top expression) by the divisor (the bottom expression). Here, both the dividend and divisor are expressed in terms of two variables, ๐‘Ž and ๐‘. We need to divide each of the terms in the polynomial by the monomial ๐‘Ž๐‘๏Šจ.

If we start by dividing each of the terms by ๐‘Ž๏Šจ, we get 26๐‘Ž7๐‘โˆ’9๐‘Ž3๐‘๐‘Ž๐‘,๏Šซ๏Šซ๏Šง๏Šซ๏Šจ which simplifies to 26๐‘Ž๐‘โˆ’9๐‘Ž๐‘๐‘.๏Šซ๏Šซ๏Šซ

Then, dividing each of the terms through by ๐‘, we get 26๐‘Ž๐‘5โˆ’9๐‘Ž๐‘5๐‘,๏Šซ๏Šช๏Šช which simplifies to 26๐‘Ž๐‘โˆ’9๐‘Ž๐‘.๏Šซ๏Šช๏Šช

In some questions, we are given the final simplified expression and need to work backward to find an unknown in the original polynomial or monomial. Here is an example of this type.

Example 4: Finding an Unknown by Dividing a Polynomial by a Monomial Then Comparing with the Final Simplified Expression

Find the value of the constant ๐‘˜, given that 4๐‘ฅ๐‘ฆ+๐‘˜๐‘ฅ๐‘ฆ2๐‘ฅ๐‘ฆ=2๐‘ฅ๐‘ฆ+3๐‘ฅ๐‘ฆ๏Šซ๏Šจ๏Šญ๏Šฉ๏Šจ๏Šฉ๏Šซ๏Šจ.

Answer

To find a quotient, we divide the dividend (the top expression) by the divisor (the bottom expression). Here, we are given the simplified quotient 2๐‘ฅ๐‘ฆ+3๐‘ฅ๐‘ฆ๏Šฉ๏Šซ๏Šจ and are shown that it arises from dividing the polynomial 4๐‘ฅ๐‘ฆ+๐‘˜๐‘ฅ๐‘ฆ๏Šซ๏Šจ๏Šญ๏Šฉ by the monomial 2๐‘ฅ๐‘ฆ๏Šจ. Therefore, we must work backward from the final quotient to find the value of the constant ๐‘˜.

To begin, notice that we can rewrite the left-hand side of the original equation as two separate terms: 4๐‘ฅ๐‘ฆ2๐‘ฅ๐‘ฆ+๐‘˜๐‘ฅ๐‘ฆ2๐‘ฅ๐‘ฆ.๏Šซ๏Šจ๏Šจ๏Šญ๏Šฉ๏Šจ

Simplifying the first term by dividing through by 2๐‘ฅ๐‘ฆ๏Šจ, we get 4๐‘ฅ๐‘ฆ2๐‘ฅ๐‘ฆ=2๐‘ฅ๐‘ฆ.๏Šซ๏Šจ๏Šจ๏Šฉ

Clearly, this matches up with the first term on the right-hand side of the original equation. This implies that the second terms must also match up, so we have ๐‘˜๐‘ฅ๐‘ฆ2๐‘ฅ๐‘ฆ=3๐‘ฅ๐‘ฆ.๏Šญ๏Šฉ๏Šจ๏Šซ๏Šจ

Now, we use this equation to find ๐‘˜. We begin by simplifying ๐‘˜๐‘ฅ๐‘ฆ2๐‘ฅ๐‘ฆ๏Šญ๏Šฉ๏Šจ by dividing through by ๐‘ฅ๐‘ฆ๏Šจ, which means the equation becomes ๐‘˜2๐‘ฅ๐‘ฆ=3๐‘ฅ๐‘ฆ.๏Šซ๏Šจ๏Šซ๏Šจ

Observe that we now have the monomial ๐‘ฅ๐‘ฆ๏Šซ๏Šจ on both sides. Therefore, we can obtain ๐‘˜ by equating the coefficients, which is the same as canceling the ๐‘ฅ๐‘ฆ๏Šซ๏Šจ on both sides. Thus, we get ๐‘˜2=3,๐‘˜=6.

We sometimes meet more general problems where the division of a polynomial by a monomial arises as part of the solution. Our final example comes from a geometric context.

Example 5: Finding an Expression for the Height of a Triangle

The area of a triangle is ๏€น12๐‘ฅ+4๐‘ฅ๏…๏Šจ cm2, and its base is 4๐‘ฅ cm. Write an expression for its height.

Answer

First, remember the formula for the area of a triangle: areaoftrianglebaseperpendicularheight=12ร—ร—.

In this question, we are given expressions for the area and base of a triangle. Hence, we can substitute them into the formula to form the equation 12๐‘ฅ+4๐‘ฅ=12ร—4๐‘ฅร—โ„Ž,๏Šจ where โ„Ž is the height. To find an expression for โ„Ž, we need to rearrange the equation to make โ„Ž the subject. We start by multiplying throughout by 2: 24๐‘ฅ+8๐‘ฅ=4๐‘ฅร—โ„Ž.๏Šจ

We then need to divide throughout by 4๐‘ฅ, which gives us โ„Ž=24๐‘ฅ+8๐‘ฅ4๐‘ฅ.๏Šจ

Notice that the right-hand side is now in the form of a quotient, where the dividend is the polynomial 24๐‘ฅ+8๐‘ฅ๏Šจ and the divisor is the monomial 4๐‘ฅ. Therefore, we need to simplify it by dividing each of the terms of the polynomial by 4๐‘ฅ, which gives us โ„Ž=24๐‘ฅ4๐‘ฅ+8๐‘ฅ4๐‘ฅ=6๐‘ฅ+2๐‘ฅ=6๐‘ฅ+2๐‘ฅ=6๐‘ฅ+2.๏Šจ(๏Šจ๏Šฑ๏Šง)(๏Šง๏Šฑ๏Šง)๏Šง๏Šฆ

As the base was given in centimetres, the height will also be in centimetres: an expression for the height of the triangle is 6๐‘ฅ+2 cm.

Let us finish by recapping some key concepts from this explainer.

Key Points

  • To divide a polynomial by a monomial, remember the following steps:
    1. Divide each of the individual terms of the polynomial by the monomial.
    2. Simplify any constants.
    3. Simplify the variable terms using the quotient rule of exponents: ๐‘ฅรท๐‘ฅ=๐‘ฅ๐‘ฅ=๐‘ฅ.๏Œบ๏Œป๏Œบ๏Œป๏Œบ๏Šฑ๏Œป
  • The quotient rule of exponents can be applied to problems involving single-variable and multivariable polynomials and monomials.
  • In cases of a multivariable denominator, it may seem easier to simplify one variable at a time.
  • It can be helpful to show your working by canceling from the top and the bottom of each expression.

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