Nagwa uses cookies to ensure you get the best experience on our website. Learn more about our Privacy Policy.

Start Practicing

Worksheet: Elastic Potential Energy


In the movie Monty Python and the Holy Grail, a cow of mass 110 kg is catapulted from the top of a castle wall 9.1 m high, onto the people down below. The cow is launched from a spring of with a constant of 1 . 1 × 1 0 4 N/m that was initially compressed by 0.50 m from equilibrium. The gravitational potential energy is set to zero at the base of the castle wall.

What is the gravitational potential energy of the cow as it just clears the castle wall, treating the cow as a point particle?

  • A 1 1 × 1 0 3 J
  • B 8 . 9 × 1 0 3 J
  • C 1 2 × 1 0 3 J
  • D 9 . 8 × 1 0 3 J
  • E 1 3 × 1 0 3 J

What is the elastic spring energy of the cow before the catapult is released?

  • A 1 . 4 × 1 0 3 J
  • B 1 . 2 × 1 0 3 J
  • C 0 . 8 9 × 1 0 3 J
  • D 0 . 6 5 × 1 0 3 J
  • E 1 . 5 × 1 0 3 J

What is the speed of the cow at the instant that it hits the ground?


A box that has 50 J of kinetic energy slides on a frictionless surface. The box hits a spring and compresses the spring a distance of 25 cm from its equilibrium length. If the same box with the same initial energy slides on a rough surface, it only compresses the spring a distance of 15 cm. How much energy must have been lost by the box when sliding on the rough surface?


The spring of a spring gun has a force constant 𝑘 = 1 2 / N c m . When the gun is aimed vertically upward, a 15-g projectile is shot to a height of 5.0 m above the end of the expanded spring, as shown in the accompanying diagram. How much was the spring compressed initially?


A pogo stick has a spring constant of 2 . 5 0 × 1 0 4 N/m. A child stands on the pogo stick, pointing the stick vertically upward and compressing it by 12.0 cm. The child and pogo stick have a combined mass of 40.0 kg. The child jumps, which exerts negligible force but causes the pogo stick to return to its equilibrium length. What is the maximum upward vertical displacement of the child?


A block of mass 230 g is attached to one end of a spring that has a spring constant of 120 N/m. The other end of the spring is attached to a support while the block rests on a smooth horizontal table and can slide freely without any friction. The block is pushed horizontally to compress the spring by 12 cm. The block is then released from rest.

How much potential energy is stored in the spring when the spring is fully compressed?

Determine the speed of the block when the spring has recoiled to its equilibrium length.


You compress a spring by 𝑥 and then release it. Next, you compress the spring by 2 𝑥 . How much more work did you do the second time than the first?

  • AHalf as much.
  • BA quarter as much.
  • CThe same.
  • DFour times as much.
  • ETwice as much.


You are loading a toy dart gun, which has two settings. The spring in the toy gun is compressed twice as far in the more powerful setting as it is in the less powerful setting. If it takes 5.0 J of work to compress the dart gun to the lower setting, how much work does it take for the higher setting?


A bungee cord exerts a nonlinear elastic restoring force of magnitude 𝐹 ( 𝑥 ) = 1 8 8 𝑥 / 0 . 6 7 2 𝑥 / N m N m 3 3 when it is extended. How much work is required to extend the bungee cord by 12.7 m?


In a Coyote/Road Runner cartoon clip, a spring expands quickly and sends the coyote into a rock. The spring extends by 5.0 m and accelerates the coyote of mass 20 kg to a speed of 15 m/s.

What is the spring constant of this spring?

If the coyote were sent vertically upward with the energy given to him by the spring, what maximum height would it reach, assuming air resistance was negligible?


A Delorean car of mass 1 2 3 0 kg travels at 88 mph. What spring constant would a spring need to have to bring the car to rest in a distance of 0.25 m?

  • A 3 . 2 × 1 0 7 N/m
  • B 1 . 7 × 1 0 7 N/m
  • C 5 . 0 × 1 0 7 N/m
  • D 3 . 0 × 1 0 7 N/m
  • E 9 . 0 × 1 0 7 N/m


A child of mass 32 kg jumps up and down on a trampoline. The trampoline exerts a spring restoring force on the child with a spring constant of 5 . 0 × 1 0 3 N/m. At the highest point of the bounce, the child is 1.0 m vertically above the unstretched surface level of the trampoline. What distance is the trampoline compressed by when the child jumps on it? Neglect the bending of the child’s legs or any transfer of energy of the child into the trampoline while jumping.


A perfectly elastic spring with an equilibrium length of 20.0 cm and a spring constant of 400.0 N/m changes in length from 22.0 cm in such a way that the elastic potential energy stored in the spring increases by 0.0800 J. What is the length of the spring after its length changes?


A perfectly elastic spring has an equilibrium length of 0.20 m and a spring constant of 0.400 kN/m. The spring is extended so that its length becomes 0.23 m.

How much elastic potential energy is contained in the spring when it is extended?

The spring is further extended so that its length becomes 0.26 m. What is the increase in the elastic potential energy due to the additional extension?


A massless spring with force constant 𝑘 = 2 0 0 / N m hangs from the ceiling. A 2.0 kg block is attached to the free end of the spring and released. If the block falls 17 cm before starting back upwards, how much work is done by friction during its descent?


386 J of work is required to compress a spring by 117 mm. What is the force constant of the spring?

  • A 4 . 6 6 × 1 0 3 N/m
  • B 3 . 2 × 1 0 4 N/m
  • C 3 . 0 4 × 1 0 4 N/m
  • D 5 . 6 4 × 1 0 4 N/m
  • E 7 . 4 3 × 1 0 4 N/m


A spring has a force constant of 53.0 N/m. An object, initially at rest, with a mass of 0.960 kg is suspended from it. The object descends, stretching the string, oscillates, and then comes to rest.

How much is the spring stretched when the object has come to rest after oscillating?

Calculate the decrease in the gravitational potential energy of the object between its position at the point at which it is attached to the unextended spring and its position at the point at which it comes to rest after oscillating.

Calculate the energy stored in the spring by its extension.


Old-fashioned pocket watches needed to be wound daily so they would not run down and lose time due to the friction in the internal components. This required a large number of turns of the winding key, but not much force per turn, and it was possible to overwind and break the watch. In which of the following ways was the energy stored?

  • AA large mass raised a short distance.
  • BA small mass raised a long distance.
  • CA strong spring deformed a short way.
  • DA weak spring deformed a long way.
  • EA weak spring deformed a short way.