Worksheet: The Mean Value Theorem
In this worksheet, we will practice interpreting and using the mean value theorem and Rolle’s theorem.
Q1:
Mason is not convinced that the mean value theorem is true because, he says, the function has the property that if we take and , we have , and yet there is no point where . What is his error?
- AThe function is not differentiable at . The theorem requires diferentiability on an interval.
- BThe theorem requires the domain to be an interval, which is not.
- CThe function is not continuous. The theorem requires continuity on an interval.
- DThe function should be strictly increasing on the interval.
- EThe function should be strictly decreasing on the interval.
Q2:
Madison is not convinced that the mean value theorem is true because, she says, the function is certainly differentiable on . But if we take and , we have , and yet there is no point where . What is her error?
- AThe function should be continuous on the interval.
- BThe theorem requires the domain to be an interval, which is not.
- CThe function should be strictly increasing on the interval.
- DThe theorem requires that the function be differentiable on its domain.
- EThe function should be strictly decreasing on the interval.
Q3:
Does the mean value theorem apply for the function over the interval ?
- ANo
- BYes
Q4:
Does the mean value theorem apply to the function over the interval ?
- ANo
- BYes
Q6:
Does the mean value theorem apply for the function over the interval ?
- AYes
- BNo
Q13:
A rock is dropped from a height of 81 ft. Its position seconds after it is dropped until it hits the ground is given by the function .
Determine how long it will take for the rock to hit the ground.
- A0 s
- B s
- C s
- D s
- E s
Find the average velocity, , of the rock from the point of release until it hits the ground.
Find the time according to the mean value theorem when the instantaneous velocity of the rock is .
- A s
- B s
- C s
- D0 s
- E s
Q16:
Consider the statement that if is a differentiable function on an interval and there, then is strictly increasing on .
Which of the following statements is equivalent to the above?
- AIf is differentiable on an interval and not strictly increasing there, then at some point .
- BIf is differentiable on an interval and not strictly increasing there, then at all points .
- CIf is differentiable on an interval and strictly increasing there, then at all points .
- DIf is differentiable on an interval and there, then is not strictly increasing on .
- EIf is differentiable on an interval and strictly increasing there, then at some point .
What does it mean for a function to not be strictly increasing on the interval ?
- AThere are points with but .
- BThere are points with but .
- CThere is a point where .
- DWhenever satisfy , then .
- EThere are points with but .
Using the equivalent statement to the main result, how can you use the mean value theorem to prove the equivalent statement?
- AIf is differentiable on and not strictly increasing, then take with . By the mean value theorem, we get between and and where , so .
- BIf is differentiable on and not strictly increasing, then take with . By the mean value theorem, we get between and where , so .
- CIf is differentiable on and not strictly increasing, then take with . By the mean value theorem, we get between and where , so .
- DIf is differentiable on and not strictly increasing, then take with . By the mean value theorem, we get between and where , so .
- EIt is not possible to prove the statement using the mean value theorem.
Q17:
Consider the result: If is differentiable on an interval and , then , a constant, for all .
Which of the following statements says exactly the same thing as the constant function result?
- AIf is differentiable on an interval and at each , then is not a constant function.
- BIf is a constant function on an interval , then is differentiable and at all .
- CIf is differentiable on an interval and at some , then is not a constant function.
- DIf is differentiable on an interval and not a constant function, then at some .
- EIf is differentiable on an interval and not a constant function, then at all .
If is differentiable on an interval and not constant, we get points with . How does this show that at some point ?
- Abecause then and by the mean value theorem, there is a point with
- Bbecause means that one of or is not zero; we can take as this point
- Cbecause only constant functions has everywhere
- Dbecause then and by the mean value theorem, there is a point with
- Ebecause if on , then would be a constant function