Worksheet: Associative Property of Multiplication

In this worksheet, we will practice identifying and applying the associative property of multiplication to multiply three one-digit numbers with products up to 10×10.

Q1:

Which of these is equal to 18×5?

Hint: Remember that you can replace one of the factors by an expression it is equal to.

  • A 8 × 2 × 5
  • B 1 0 × 8 × 5
  • C 9 × 9 × 5
  • D 9 × 2 × 5

Q2:

To draw a model to show (7×4)×2, Olivia draws an array to show 7×4 and uses the third number to tell her how many copies to make.

How can she draw a model to show 7×(4×2)?

  • A
  • B
  • C
  • D

Is there the same number of squares in each model?

  • Ano
  • Byes

Which equation do the models prove?

  • A ( 7 × 4 ) × 2 = 7 + ( 4 × 2 )
  • B ( 7 × 4 ) × 2 = 7 + ( 4 + 2 )
  • C ( 7 × 4 ) × 2 = 7 × ( 4 × 2 )
  • D ( 7 × 4 ) × 2 = 7 × ( 4 + 2 )

Q3:

Compare the expressions. Pick the symbol that is missing.

  • A =
  • B >
  • C <

Q4:

Scarlett drew 5 arrays with 2 rows and 3 columns.

Use her picture to find the missing number. 5×6=5××3.

Find another expression that is equal to 5×6.

  • A 1 0 × 3
  • B 1 1 × 1
  • C 4 × 8
  • D 4 × 7

Q5:

When we multiply three numbers, we can choose which calculation to do first.

Do the highlighted calculations to find the missing numbers.

What is 6×5×2?

Q6:

Daniel knows that you can break apart numbers to make calculations easier.

Finish his calculation to find the answer. 35×2=7×5×2=7×10=?

Pick one way to break apart one of the factors to solve 5×16.

  • A 5 × 2 × 8
  • B 5 × 1 0 × 6
  • C 5 × 3 × 8
  • D 5 × 1 × 6

Which of these is equal to 5×16?

  • A 1 0 × 8 = 8 0
  • B 1 5 × 8 = 1 2 0
  • C 5 × 6 = 3 0
  • D 5 0 × 6 = 3 0 0

Q7:

Complete: 10×4×7=10×.

Q8:

Multiplying by 2 and 10 is easy!

Let’s rewrite this expression to make it easier.

Which of these is equal to 14×5?

  • A 6 × 1 0
  • B 7 × 1 0
  • C 1 0 × 1 0
  • D 1 2 × 1 0

What is 14×5?

Q9:

Fill in the blank: 93×96×43=×43×93.

Q10:

We can use the associative property to help us multiply.

Find the missing factor. 16×5=(×2)×5.

Find the missing product. 16×5=.

Q11:

David found a way to make 10 so he can multiply more easily.

Find the missing numbers using his strategy.

3 6 × 5 = × 1 0

2 × 3 5 = 1 0 ×

1 8 × 5 =

Q12:

Ethan and Scarlett know that they can multiply 3 numbers in any order.

They both find an expression that is equal to 7×4×5.

Ethan can’t solve 28×5. Use Scarlett’s expression to find the answer to 7×4×5.

If we don’t know 28×5, we can write 28 as and then solve 7×4×5 by first making 20.

  • A 7 × 4
  • B 6 × 5
  • C 6 × 3
  • D 8 × 3

Q13:

Rectangle C is made of 2 copies of Rectangle A. So, its area is 2 times as much as the area of Rectangle A.

Pick another expression that is equal to the area of Rectangle C.

  • A 2 × ( 3 × 5 )
  • B 3 × ( 3 × 5 )
  • C 2 × ( 2 × 5 )
  • D ( 2 × 3 ) + ( 3 × 5 )

Rectangle D is made from 5 copies of Rectangle B.

Rectangle C has the same area as Rectangle D. Finish the equation by finding the expression in the parentheses.

  • A 5 × 3
  • B 2 × 5
  • C 3 × 3
  • D 2 × 3

Q14:

Given that 𝑥×(8×17)=(9×(8))×17, find the value of 𝑥.

Q15:

Complete: 10×7×5=10×.

Q16:

Find a three-digit number whose digits have a product of 7.

  • A107
  • B127
  • C217
  • D117

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