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Worksheet: Circuits with Resistors and Inductors in Series

Q1:

How long after switch 𝑆 1 is thrown does it take the current in the circuit shown to reach half its maximum value? Express your answer in terms of the time constant of the circuit.

  • A 0 . 5 0 𝜏
  • B 0 . 3 3 𝜏
  • C 0 . 6 7 𝜏
  • D 0 . 6 9 𝜏
  • E 0 . 8 1 𝜏

Q2:

The current in the RL circuit shown below reaches half its maximum value in 1.75 ms after the switch 𝑆 1 is thrown.

Determine the time constant of the circuit if 𝐿 = 2 5 0 m H .

Determine the resistance of the circuit if 𝐿 = 2 5 0 m H .

Q3:

The switch of the circuit shown is closed at .

Determine the initial current through the battery.

Determine the steady-state current through the battery.

Q4:

For the circuit shown, emf πœ€ = 2 0 V, inductance 𝐿 = 4 . 0 m H , and resistance 𝑅 = 5 . 0 Ξ©. Steady state is reached with S 1 closed and S 2 open. S 2 is then closed and immediately afterwards (at 𝑑 = 0 ) S 1 is opened.

Determine the current through 𝐿 at 𝑑 = 0 .

Determine the current through 𝐿 at 𝑑 = 4 . 0 Γ— 1 0 βˆ’ 4 s .

Determine the voltage across 𝐿 at 𝑑 = 4 . 0 Γ— 1 0 βˆ’ 4 s .

Determine the voltage across 𝑅 at 𝑑 = 4 . 0 Γ— 1 0 βˆ’ 4 s .

Q5:

A resistor and a self-inductor are connected in series to a source of emf, creating an RL circuit. The current through the circuit increases to 20% of its steady-state value in 3.0 s. What is the time constant of the circuit?

Q6:

Consider the circuit shown with πœ€ = 2 0 V , 𝑅 = 8 . 0 1 Ξ© , and 𝑅 = 2 . 0 2 Ξ© .

Find 𝐼 1 at the instant switch 𝑆 is first closed.

Find 𝐼 2 at the instant switch 𝑆 is first closed.

Find 𝐼 3 at the instant switch 𝑆 is first closed.

Find 𝐼 3 after the currents have reached steady-state values.

Find 𝐼 2 after the currents have reached steady-state values.

Find 𝐼 1 after the currents have reached steady-state values.

Q7:

For the circuit shown, πœ€ = 6 0 V , 𝑅 = 5 . 0 1 Ξ© , 𝑅 = 2 . 0 2 Ξ© , and 𝑅 = 4 . 0 3 Ξ© . Find the current through the inductor after the currents have reached steady-state values.

Q8:

For the circuit shown, πœ€ = 6 0 V , 𝑅 = 5 . 0 1 Ξ© , 𝑅 = 2 . 0 2 Ξ© , 𝑅 = 4 . 0 3 Ξ© , and 𝐿 = 4 . 0 H . Find the current through the inductor 3 . 0 Γ— 1 0 βˆ’ 5 s after the switch is reopened.

  • A 4 1 Γ— 1 0 βˆ’ 4 A
  • B 5 . 5 Γ— 1 0 βˆ’ 4 A
  • C 9 . 2 Γ— 1 0 βˆ’ 4 A
  • D 4 . 5 Γ— 1 0 βˆ’ 4 A
  • E 6 . 7 Γ— 1 0 βˆ’ 4 A

Q9:

The switch in the circuit shown is closed at 𝑑 = 0 s .

Find the current through 𝑅 1 .

Find the current through 𝑅 2 .

Find the current through the battery at 𝑑 = 2 . 0 s .