Lesson Worksheet: Investigating Photosynthesis Biology
In this worksheet, we will practice describing practical experiments that can be used to investigate the effect of limiting factors on the rate of photosynthesis.
The following equation shows the relationship between the distance of a light source and the light intensity: .
If the distance between the plant and the light source halves, what happens to the rate of photosynthesis?
- ANo change occurs.
- DIt triples.
What gas is produced by plants when they photosynthesize?
- ACarbon dioxide
The diagram shows a simple set of the equipment used to investigate the effect of light intensity on the rate of photosynthesis in pondweed.
Using this equipment, how can the rate of photosynthesis be measured?
- ADistance number of bubbles produced
- BNumber of bubbles produced distance
- CDistance time
- DNumber of bubbles produced time
In this experiment, what is the independent variable?
- ATemperature of water
- BBubbles produced
- CLight intensity
- DCarbon dioxide concentration
The diagram provided shows the experimental setup for investigating the effect of light intensity on the rate of photosynthesis in algal balls.
Equal numbers of algal balls are added to 50 cm3 of hydrogencarbonate indicator solution and covered with lids.
As the concentration of increases in the solution, the solution turns more yellow.
As the concentration of decreases in the solution, the solution turns more purple.
Which of the following correctly describes the relationship between concentration and the rate of photosynthesis?
- AThe more the algal balls photosynthesize, the more will be in the hydrogencarbonate solution.
- BThere is no link between the rate of photosynthesis and in the hydrogencarbonate solution.
- CThe less the algal balls photosynthesize, the less will be in the surrounding atmosphere.
- DThe more the algal balls photosynthesize, the less will be in the hydrogencarbonate solution.
In which of the 5 bottles will photosynthesis be happening the fastest?
Which of the 5 bottles will contain the greatest amount of remaining in the solution?
When investigating the effect of light intensity on the rate of photosynthesis, a vial or beaker of water is often placed in between the lamp and the plant, as shown in the diagram. Which of the following best explains why?
- ATo replicate the effect of natural sunlight more closely
- BTo absorb the heat from the lamp so the light intensity is the only variable that changes
- CTo absorb the light from the lamp so it is always kept constant
- DTo ensure the light intensity does not get too high and denature the enzymes needed for photosynthesis
- ETo prevent the plant from being influenced by other sources of light
When it is not needed by the plant, the glucose made in photosynthesis can be stored as starch. Iodine can be used to test a leaf for the presence of starch in a process outlined in the diagram provided.
In step 2, why is the leaf boiled in ethanol?
- ATo break down the nuclear membrane
- BTo break down the cell walls
- CTo make the leaf less reactive
- DTo remove the green pigment
What color will the iodine turn into if starch is present in the leaf?
- ABrick red
- DDark green
The table provided shows an example set of results for a student’s investigation into the effect of light intensity on the rate of photosynthesis. The student timed how long it took a plant to release 10 bubbles at each light intensity.
|Relative Light Intensity||Time (s)||Relative Rate of Photosynthesis (s−1)|
Calculate the missing value using the following equation: relative rate of reaction = 1 time. Give your answer to 4 decimal places.
To calculate light intensity, the following equation can be used:
The plant starts 1 cm away from the light, which is emitting 1 lux of light.
The light is turned on and the plant is moved to be 5 cm away from the light source. What is the new light intensity?
The inverse square law provided can be used to calculate light intensity using the distance a light source is from an object (, ).
If the new light intensity is 800 luxes when the light source is at a distance of 12 centimeters, what was the original light intensity when the light source was 6 centimeters away?
The inverse square law provided can be used to calculate light intensity, using the distance a light source is from an object ( = light intensity, = distance).
If the original light intensity is 500 luxes when the light source is at a distance of 10 centimetres, what is the new light intensity when the light source is moved to 5 centimetres away from the object?