Worksheet: Kc to Kp Conversions

In this worksheet, we will practice converting between equilibrium constants defined by partial pressures and those defined by concentration.

Q1:

For the reaction shown, ๐พ=1.22ร—10P๏Šฑ๏Šง at 50โˆ˜C. HO()HO()22lg If partial pressures are measured relative to a standard pressure of 1 atm, what is the value of ๐พc at this temperature to three significant figures?

  • A2.93ร—10๏Šฑ๏Šช
  • B1.22ร—10๏Šฑ๏Šง
  • C4.54ร—10๏Šฑ๏Šซ
  • D2.97ร—10๏Šฑ๏Šจ
  • E4.60ร—10๏Šฑ๏Šฉ

Q2:

For the reaction shown, ๐พ=4.08ร—10P๏Šฑ๏Šจ๏Šซ at 25โˆ˜C. NaSOยท10HO()NaSO()+10HO()242242ssg If partial pressures are measured relative to a standard pressure of 1 atm, what is the value of ๐พc at this temperature? Give your answer to two significant figures.

  • A4.66ร—10๏Šฑ๏Šซ๏Šฏ
  • B3.09ร—10๏Šฑ๏Šจ๏Šฎ
  • C4.08ร—10๏Šฑ๏Šจ๏Šซ
  • D2.71ร—10๏Šฑ๏Šช๏Šฎ
  • E5.31ร—10๏Šฑ๏Šฉ๏Šฏ

Q3:

For the reaction shown, ๐พ=0.502ร—10c๏Šจ at 448โˆ˜C. H()+I()2HI()22ggg If partial pressures are measured relative to a standard pressure of 1 bar, what is the value of ๐พP at this temperature?

  • A3.01ร—10๏Šซ
  • B0.502ร—10๏Šจ
  • C2.97ร—10๏Šฉ
  • D8.48ร—10๏Šฑ๏Šง
  • E1.85ร—10๏Šฉ

Q4:

For the reaction shown, ๐พ=5ร—10c๏Šฑ๏Šง at 400โˆ˜C. N()+3H()2NH()223ggg If partial pressures are measured relative to a standard pressure of 1 bar, what is the value ๐พP at this temperature to two significant figures?

  • A1.6ร—10๏Šฑ๏Šฎ
  • B4.6ร—10๏Šฑ๏Šช
  • C9.0ร—10๏Šฑ๏Šฉ
  • D5ร—10๏Šฑ๏Šง
  • E1.6ร—10๏Šฑ๏Šช

Q5:

What is the equation for the conversion of ๐พc to ๐พP for the reaction shown? CH()CH()+H()26242ggg

  • A๐พ=๐พ(๐‘…๐‘‡)Pc๏Šจ
  • B๐พ=๐พ(๐‘…๐‘‡)Pc๏Šจ
  • C๐พ=๐พ๐‘…๐‘‡Pc
  • D๐พ=๐พ๐‘…๐‘‡Pc
  • E๐พ=๐พPc

Q6:

What is the equation for the conversion of ๐พc to ๐พP for the following reaction? CO()+HO()CO()+H()gggg222

  • A๐พ=๐พ๐‘…๐‘‡pc
  • B๐พ=๐พ๐‘…๐‘‡pc
  • C๐พ=๐พpc
  • D๐พ=๐พ(๐‘…๐‘‡)pc๏Šจ
  • E๐พ=๐พ(๐‘…๐‘‡)pc๏Šจ

Q7:

What is the equation for the conversion of ๐พc to ๐พP for the reaction shown? N()+3H()2NH()223ggg

  • A๐พ=๐พ๐‘…๐‘‡Pc
  • B๐พ=๐พ(๐‘…๐‘‡)Pc๏Šจ
  • C๐พ=๐พ๐‘…๐‘‡Pc
  • D๐พ=๐พPc
  • E๐พ=๐พ(๐‘…๐‘‡)Pc๏Šจ

Q8:

๐พc is equal to 28ร—10๏Šฑ๏Šจ for the reaction shown at 900โˆ˜C. CS()+4H()CH()+2HS()2242gggg. Under standard conditions, all species have a concentration of 1.00 M and partial pressure of 1.00 atm. Calculate ๐พP for this reaction at 900โˆ˜C to two significant figures.

  • A5.1ร—10๏Šฑ๏Šซ
  • B1.5ร—10๏Šฉ
  • C3.0ร—10๏Šฑ๏Šซ
  • D2.6ร—10๏Šฉ
  • E28ร—10๏Šฑ๏Šจ

Q9:

What is the equation for the conversion of ๐พc to ๐พP for the reaction shown? 2SO()+O()2SO()223ggg

  • A๐พ=๐พ๐‘…๐‘‡Pc
  • B๐พ=๐พPc
  • C๐พ=๐พ(๐‘…๐‘‡)Pc๏Šจ
  • D๐พ=๐พ(๐‘…๐‘‡)Pc๏Šจ
  • E๐พ=๐พ๐‘…๐‘‡Pc

Q10:

What is the equation for the conversion of ๐พc to ๐พP for the reaction shown? NO()2NO()242gg

  • A๐พ=๐พ(๐‘…๐‘‡)Pc๏Šจ
  • B๐พ=๐พPc
  • C๐พ=๐พ๐‘…๐‘‡Pc
  • D๐พ=๐พ(๐‘…๐‘‡)Pc๏Šจ
  • E๐พ=๐พ๐‘…๐‘‡Pc

Q11:

What is the equation for the conversion of ๐พc to ๐พP for the reaction shown? CH()+5O()3CO()+4HO()38222gggg

  • A๐พ=๐พ๐‘…๐‘‡Pc
  • B๐พ=๐พ(๐‘…๐‘‡)Pc๏Šจ
  • C๐พ=๐พ๐‘…๐‘‡Pc
  • D๐พ=๐พ(๐‘…๐‘‡)Pc๏Šจ
  • E๐พ=๐พPc

Q12:

At 227โˆ˜C, the following reaction has ๐พ=9.52ร—10c๏Šฑ๏Šจ. CHOH()CO()+2H()32ggg Under standard conditions, the concentration of each species is 1.00 M and the partial pressure is 1.00 bar. Calculate ๐พP for this reaction at 227โˆ˜C to three significant figures.

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