**Q1: **

A particle moves in a plane in which and are perpendicular unit vectors. A force, acts on the particle. The particle moves from the origin to the point with position vector m. Find the work done by the force.

**Q2: **

A force acts on a particle, causing a displacement . If the work done by the force is 0.02 J, what is the value of ?

**Q3: **

A particle moved from point to point along a straight line under the action of the force acting in the opposite direction to the displacement . Find the work done by the force .

**Q4: **

A particle moved on a plane from the point to the point under the action of a force of 17 N whose line of action made an angle of with the -axis where . Find the work done by this force over the displacement .

- A or work units
- B142 or work units
- C or 158 work units
- D65 or 95 work units

**Q5: **

A particle moved from point to point along a straight line under the action of the force . During this stage of motion, the work done by the force was 106 units of work. The particle then moved from to another point under the effect of the same force. During this stage of motion, the work done by the force was units of work. Determine the two constants and .

- A,
- B,
- C,
- D,

**Q6: **

A particle is moving in a straight line under the action of a constant force of magnitude 47 N acting in the direction of motion. The displacement of the particle is given by the relation , where is a unit vector parallel to the direction of motion. Given that the displacement is measured in meters, find the work done, in joules, by this force in the first 9 seconds of motion.

- A114 210joules
- B116 325joules
- C114 255joules
- D38 305joules

**Q7: **

A particle moved from point to point along a straight line under the action of a force of magnitude N acting in same direction as the vector . Calculate the work done by the force, given that the magnitude of the displacement is measured in meters.

- A J
- B344 J
- C8 J
- D424 J

**Q8: **

A particle moved from point to point along a straight line under the action of a force of magnitude N acting in same direction as the vector . Calculate the work done by the force, given that the magnitude of the displacement is measured in meters.

- A J
- B J
- C420 J
- D810 J

**Q9: **

A body of mass 3 kg is moving under the action of a force , such that its displacement . Find the work done by this force in the first 6 seconds of its motion, given that the displacement is measured in meters, the force in newtons, and the time in seconds.

- A2 700J
- B5 400J
- C7 560J
- D900 J

**Q10: **

The displacement of a particle of mass 30 g is given as a function of time by the relation , where is a constant unit vector, is measured in centimeters, and in seconds. Given that the particle started its motion at , find the force acting on the particle and the work done by this force during the first 7 seconds of motion.

- A dynes, ergs
- B dynes, ergs
- C dynes, ergs
- D dynes, ergs

**Q11: **

A particle moves in a plane in which and are perpendicular unit vectors. Its displacement from the origin at time t seconds is given by and it is acted on by a force . how much work does the force do between and ?

**Q12: **

The position vector of a particle of mass 3 kg moving under the action of a force is given as a function of time by the relation , where and are two perpendicular unit vectors. Calculate the work done by the force between to .

**Q13: **

A body of mass 2 kg is moving under the action of three forces, , , and , where , , and , and and are two perpendicular unit vectors, and are constants, and each force is measured in newtons. The displacement of the body is expressed by the relation , where the displacement is measured in meters, and the time is in seconds. Determine the work done by the resultant of the forces in the first 6 seconds of motion.

- A1 584J
- B3 024J
- C J
- D3 120J