### Video Transcript

Sketch the graph of π¦ is equal to
sin of π₯ degrees for zero is less than or equal to π₯, which is less than or equal
to 360.

Letβs think about what we know
about the trigonometric graph π¦ is equal to sin of π₯ degrees. First, we know that itβs a periodic
graph. That means it repeats and then it
does so every 360 degrees. We also know that it has a maximum
π¦-value of one and a minimum π¦-value of negative one. Finally, itβs useful to remember
that the sin curve passes through the π¦-axis at zero, whereas the cos graph passes
through at one.

As long as we remember these facts
and the general shape which is a wave, the next part is just to sketch it. The sin curve has rotational
symmetry about the point 180 degrees zero. The graph of π¦ is equal to sin π₯
is as shown.

Remember since the question says to
sketch the graph, it doesnβt need to be perfectly to scale. It should, however, include all the
relevant points of intersection with the axes and the turning point should be
roughly in the right place. Itβs also useful to know what to do
if weβre asked to sketch the graph over a different domain.

In this case, the domain is π₯ has
got to be greater than or equal to zero, but less than or equal to 360 degrees. If this domain was larger, for
example, up to 720 degrees, weβd remember that the graph is periodic. It repeats every 360 degrees. So we can continue the wave shape
that we already have.

The graph of π¦ is equal to π of
π₯ is shown on both grids below.

Part one, On the first grid, draw
the graph of π¦ is equal to a half π of π₯.

Letβs recall the notation. When we see a function π¦ is equal
to π of π₯, that just means that itβs an equation for π¦ in terms of π₯. π of π₯ could really be any
function such as π₯ squared or four π₯ cubed. Since we donβt know the exact
equation though, we just write π¦ is equal to π of π₯.

For a function π of π₯, we can
perform several transformations. π multiplied by π of π₯ is a
stretch in the π¦-direction by a scale factor of π, whereas π of π multiplied by
π₯ is a stretch in the π₯-direction by a scale factor of one over π.

Letβs compare these
transformations, which are both structures, to the equation that weβve been
given. π¦ is equal to a half of π of π₯
looks just like the first transformation function. In this case, multiplying a whole
function by π lead to a stretch in the π¦-direction by a scale factor of π. That means then that π¦ is equal to
a half multiplied by π of π₯ is a stretch in the π¦-direction by a scale factor of
one-half.

Letβs look at what happens to each
of our coordinates. Halving the value of the output,
which is the π¦-coordinate, means the coordinate negative four, two becomes negative
four, one. The coordinate negative two, two
becomes negative two, one. The coordinate negative one, zero
stays the same since half of zero is still zero. Zero, negative two becomes zero,
negative one. One, negative two becomes one,
negative one. Two, negative one becomes two,
negative a half. And three, negative one becomes
three, negative a half.

We can now see that our function π
of π₯ has been stretched in the π¦-direction by a scale factor of one-half. It looks like itβs been
compressed.

Part two, On the second grid, draw
the graph of π¦ is equal to π of π₯ plus two.

For the function π of π₯, the
graph of π of π₯ plus π is a translation by the vector zero, π. And the graph of π of π₯ plus π
is a translation by the vector negative π, zero. Once again, we need to compare the
function weβve been given with the transformations listed.

In this case, something is being
added to the π₯ before the function is applied. In our list, that looks like π of
π₯ plus π, which leads to a translation by the vector negative π, zero. That means our graph is going to be
translated by the vector negative two, zero. Thatβs two units left. When we move this first coordinate
two units left, it goes from negative four, two to negative six, two. The coordinate negative two, two
goes to negative four, two and so on.

The graph of π¦ is equal to π of
π₯ plus two has been translated two units to the left. Itβs also worth noting that there
are two further transformations that we need to be able to apply: negative π of π₯
is a reflection in the π₯-axis and π of negative π₯ is a reflection in the
π¦-axis.