Question Video: Identifying the Observation That Would Be Made When Silver Nitrate Is Combined with Chloride Ions | Nagwa Question Video: Identifying the Observation That Would Be Made When Silver Nitrate Is Combined with Chloride Ions | Nagwa

Question Video: Identifying the Observation That Would Be Made When Silver Nitrate Is Combined with Chloride Ions Chemistry • Third Year of Secondary School

The following is an incomplete table. It shows student observations for the reaction of silver nitrate with different halide ions. What term should be in the empty cell of the observation row?

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Video Transcript

The following is an incomplete table. It shows student observations for the reaction of silver nitrate with different halide ions. What term should be in the empty cell of the observation row? (A) Red precipitate, (B) orange precipitate, (C) blue precipitate, (D) white precipitate, (E) green precipitate.

In this question, we need to identify which observation is for the reaction of silver nitrate with chloride ions. During qualitative analysis, chemists often use aqueous silver nitrate to analyze the composition of a substance to determine the type of halide ion it contains. Qualitative analysis involves methods for identifying substances present in chemical samples. These techniques can only reveal if a certain chemical substance is present, not how much of a chemical substance is in a sample.

In the chemical test described in this problem, a student adds an aqueous solution of silver nitrate to samples containing different halide ions. Scientists can distinguish between the types of halide ions, because they have different reactions with the silver ions in the silver nitrate solution.

Let’s clear some space to discuss the results of these tests. When silver nitrate solution is added to a sample containing fluoride ions, the fluoride ions do not react with the silver ions. And no precipitate is formed during the reaction. However, iodide ions do react with the silver ions to form a yellow precipitate of silver iodide. Bromide ions also react with silver ions, but a cream-colored precipitate of silver bromide forms instead.

Finally, chloride ions do react with silver ions. And the white precipitate silver chloride is formed. We can see that the color of the silver chloride precipitate is noticeably different from the color of the silver bromide and silver iodide precipitates. So, we have determined that the observation that would be made when silver nitrate is combined with chloride ions is the formation of a white precipitate.

In conclusion, the term that should be in the empty cell of the observation row is white precipitate, or answer choice (D).

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