### Video Transcript

Determine the integral of seven divided by four π₯ minus six times π to the power of negative two π₯ with respect to π₯.

The question is asking us to evaluate the integral of the difference between two functions. Our integrand is the difference between a reciprocal function and an exponential function. And we know how to integrate reciprocal functions and exponential functions. So weβll rewrite our integral of the difference between two functions as the difference between two integrals. So doing this to the integral given to us in the question, we get the integral of seven divided by four π₯ with respect to π₯ minus the integral of six times π to the power of negative two π₯ with respect to π₯. Before we evaluate each of these integrals separately, remember for a constant π the integral of π times π of π₯ with respect to π₯ is equal to π times the integral of π of π₯ with respect to π₯.

So in our first integral, we can take out our constant factor of seven over four. And in our second integral, we can take out our constant factor of six. This gives us seven over four times the integral of one over π₯ with respect to π₯ minus six times the integral of π to the power of negative two π₯ with respect to π₯. Weβre now ready to evaluate each of these integrals separately. Letβs start with the integral of the reciprocal function with respect to π₯. The integral of the reciprocal function with respect to π₯ is a standard integral which we should know. Itβs the natural logarithm of the absolute value of π₯ plus the constant of integration πΆ. So evaluating our first integral we get seven over four times the natural logarithm of π₯ plus the constant of integration weβll call πΆ one.

We now want to evaluate our second integral, which is the integral of π to the power of negative two π₯ with respect to π₯. This is the integral of an exponential function. And we know how to integrate exponential functions. For any constant π, where π is not equal to zero, the integral of π to the power of ππ₯ with respect to π₯ is equal to π to the power of ππ₯ divided by π plus the constant of integration πΆ. We need to divide by the coefficient of π₯ in our exponent. In this case, we see the coefficient of π₯ in our exponent is negative two. So our value of π is negative two. And this tells us the integral of π to the power of negative two π₯ with respect to π₯ is equal to π to the power of negative two π₯ divided by negative two plus our constant of integration weβll call πΆ two.

The next thing weβll do is simplify this expression by distributing our coefficients over our parentheses. Distributing seven over four over our first set of parentheses, we get seven over four times the natural logarithm of the absolute value of π₯ plus seven πΆ one divided by four. And distributing negative six over our second set of parentheses, we get three π to the power of negative two π₯ minus six πΆ two. And weβll do one last thing to simplify this expression. Since πΆ one and πΆ two are both constants of integration, seven πΆ one over four minus six πΆ two is just a constant. So weβll combine these into one constant, weβll call πΆ.

And this gives us our final answer. The integral of seven divided by four π₯ minus six times π to the power of negative two π₯ with respect to π₯ is equal to seven over four times the natural logarithm of the absolute value of π₯ plus three times π to the power of negative two π₯ plus πΆ.