### Video Transcript

Given that π₯ is equal to negative
three, negative two, one, five, negative eight, negative eight. π¦ is equal to negative one, eight,
negative nine, negative nine, seven, negative two. And π§ is equal to three, negative
eight, negative seven, zero, negative eight, five. What is the matrix three π₯ plus π¦
minus three π§?

Our three matrices π₯, π¦, and π§
are all of the same order. That is, they have the same number
of rows and the same number of columns. And so working out three π₯ plus π¦
minus three π§ is fairly straightforward. Letβs begin with three π₯.

Three π₯ is three times negative
three, negative two, one, five, negative eight, negative eight. And to multiply a matrix by a
constant scalar, we simply multiply each of its elements. Three multiplied by negative three
is negative nine. Three multiplied by negative two is
negative six. Three times one is three. This element here is three times
five, which is 15. And the elements in our bottom row
are three times negative eight each. So thatβs negative 24. And so we know the value of three
π₯.

Weβre now going to work out the
value of three π§. Itβs three times each of the
elements in the matrix π§, three, negative eight, negative seven, zero, and negative
eight, five. The elements in our first row are
three times three and three times negative eight. So thatβs nine and negative 24. We multiply negative seven and zero
by three to get negative 21 and zero. And the final two elements are
negative 24, 15. So three π₯ plus π¦ minus three π§
is now negative nine, negative six, three, 15, negative 24, negative 24 plus
negative one, eight, negative nine, negative nine, seven, negative two minus nine,
negative 24, negative 21, zero, negative 24, 15.

Now, one of the properties of
matrices of the same orders if weβre adding or subtracting those matrices, we simply
add or subtract their respective elements. So the first element in our matrix
is the sum of negative nine and negative one minus nine. Well, thatβs negative 19. We then have negative six plus
eight minus negative 24, which is 26. Three plus negative nine minus
negative 21 is 15. 15 plus negative nine minus zero is
six. Then, for the bottom-left element,
we have negative 24 plus seven minus negative 24, which is simply seven. And then, our very final element is
negative 24 plus negative two minus 15, which is negative 41.

And so the matrix three π₯ plus π¦
minus three π§ is negative 19, 26, 15, six, seven, negative 41.