Question Video: Expressing the Sum of Three Definite Integrals over Adjacent Intervals as One Integral | Nagwa Question Video: Expressing the Sum of Three Definite Integrals over Adjacent Intervals as One Integral | Nagwa

Question Video: Expressing the Sum of Three Definite Integrals over Adjacent Intervals as One Integral Mathematics • Third Year of Secondary School

The function 𝑓 is continuous on ℝ. Write ∫_(−2) ^(3) 𝑓(𝑥) d𝑥 + ∫_(3) ^(4) 𝑓(𝑥) d𝑥 − ∫_(−2) ^(0) 𝑓(𝑥) d𝑥 in the form ∫_(𝑎) ^(𝑏) 𝑓(𝑥) d𝑥.

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Video Transcript

The function 𝑓 is continuous on all real numbers. Write the integral from negative two to three of 𝑓 of 𝑥 with respect to 𝑥 plus the integral from three to four of 𝑓 of 𝑥 with respect to 𝑥 minus the integral from negative two to zero of 𝑓 of 𝑥 with respect to 𝑥 in the form the integral from 𝑎 to 𝑏 of 𝑓 of 𝑥 with respect to 𝑥.

We know that if capital 𝐹 of 𝑥 is the antiderivative of 𝑓 of 𝑥, then the integral from a lower bound 𝑙 to an upper bound 𝑢 of 𝑓 of 𝑥 with respect to 𝑥 is equal to evaluating our antiderivative at 𝑢 and subtracting this from our antiderivative evaluated at 𝑙. If the function 𝑓 is continuous across its domain, then the integral from 𝑙 to 𝑢 of 𝑓 of 𝑥 with respect to 𝑥 is equal to capital 𝐹 of 𝑢 minus capital 𝐹 of 𝑙. We can use this rule to rewrite the three integrals given in this question.

Firstly, the integral from negative two to three of 𝑓 of 𝑥 with respect to 𝑥 is equal to capital 𝐹 of three minus capital 𝐹 of negative two. We can do the same with the integral from three to four of 𝑓 of 𝑥 with respect to 𝑥. This is equal to capital 𝐹 of four minus capital 𝐹 of three. Finally, we can write the last integral from negative two to zero of 𝑓 of 𝑥 with respect to 𝑥 as capital 𝐹 of zero minus capital 𝐹 of negative two.

Note that we need to subtract this. This means that our expression is equal to capital 𝐹 of three minus capital 𝐹 of negative two plus capital 𝐹 of four minus capital 𝐹 of three minus capital 𝐹 of zero plus capital 𝐹 of negative two. Next, we can simplify the expression by canceling terms. We have capital 𝐹 of four minus capital 𝐹 of zero. This means that the expression given to us in the question is equal to evaluating the antiderivative of capital 𝐹 of four and subtracting the antiderivative of capital 𝐹 evaluated at zero.

Finally, as the function 𝑓 is continuous for all real values and since capital 𝐹 is the antiderivative of 𝑓, we can use the same rule to rewrite this expression as the integral from zero to four of 𝑓 of 𝑥 with respect to 𝑥. The values of 𝑎 and 𝑏 are therefore equal to zero and four, respectively.

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