Question Video: Calculating the Area over Which a Pressure is Exerted | Nagwa Question Video: Calculating the Area over Which a Pressure is Exerted | Nagwa

Question Video: Calculating the Area over Which a Pressure is Exerted Physics • Second Year of Secondary School

A dancer with a mass of 50 kg is standing on the tips of the toes of one of her feet. She exerts a pressure of 490 kPa on the tips. What is the area, in square centimeters, of the part of the foot on which she stands?

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Video Transcript

A dancer with a mass of 50 kilograms is standing on the tips of the toes of one of her feet. She exerts a pressure of 490 kilopascals on the tips. What is the area, in square centimeters, of the part of the foot on which she stands?

Okay, so we’re told that there’s a dancer standing on the tips of the toes of one of her feet. Let’s suppose that this here is the dancer. We’re told that her mass is 50 kilograms, and we’ll label this mass as 𝑚. We’re also told that she exerts a pressure of 490 kilopascals on the tips of her toes. Let’s label this pressure as 𝑃. The question’s asking us to work out the area of the part of the foot she stands on. So that’s the area of her foot that’s in contact with the floor. This is the area through which all of the weight force of the dancer must act. The weight force will act vertically downward, and we’ll label it as 𝐹.

Now, we can recall that the weight of an object is equal to the object’s mass multiplied by the acceleration due to gravity. The acceleration due to gravity is denoted as a lowercase 𝑔, and on Earth it has a value of 9.8 meters per second squared. So the weight force 𝐹 of the dancer, which is the force that goes through the tips of her toes, is equal to the dancer’s mass 𝑚 multiplied by the acceleration due to gravity 𝑔. Substituting in our values for 𝑚 and 𝑔, we get that this force 𝐹 is equal to 50 kilograms multiplied by 9.8 meters per second squared. Since the mass is given in units of kilograms, which is the SI base unit for mass, and the acceleration due to gravity is in meters per second squared, the SI base unit for acceleration, then the weight force that we’ll calculate from these values must be in the SI base unit for force, which is the newton. Evaluating this expression, we find that 𝐹 is equal to 490 newtons.

We can now add this force value to our diagram. Remember that what we’re trying to find is the area through which this force acts. We can recall that whenever a force 𝐹 acts over an area 𝐴, the pressure exerted by that force is given by 𝑃 is equal to 𝐹 divided by 𝐴. In this case, we know the value of the force 𝐹 and we know the value of the pressure 𝑃. We’re trying to work out the value of the area 𝐴. This means that we want to take this equation and rearrange it to make 𝐴 the subject.

To do that, we first multiply both sides of the equation by 𝐴. Then, on the right-hand side, the 𝐴 in the numerator cancels with the 𝐴 in the denominator. We then divide both sides of the equation by 𝑃. Now, on the left-hand side, the 𝑃 in the numerator and the 𝑃 in the denominator cancel out. This leaves us with an equation that says area 𝐴 is equal to force 𝐹 divided by pressure 𝑃.

Before we substitute our values for 𝐹 and 𝑃 into this equation, we should convert our pressure 𝑃 from units of kilopascals into units of pascals, which is the SI unit for pressure. The unit prefix kilo- means a factor of 1000, and so one kilopascal is equal to 1000 pascals. In other words, to convert a pressure from kilopascals into pascals, we need to multiply the value by 1000. That means that the pressure exerted by this dancer’s weight force is equal to 490 multiplied by 1000 pascals. This works out as 490000 pascals.

Now that we’ve converted the pressure into pascals, we’re ready to sub our values for the force 𝐹 and the pressure 𝑃 into this equation to calculate the value of the area 𝐴. With a force measured in newtons and a pressure in pascals, we’ll calculate an area in the SI unit for area, which is meters squared. Substituting in the values for 𝐹 and 𝑃 and then evaluating this expression, we calculate that the area of the dancer’s foot in contact with the floor is equal to 0.001 meters squared.

However, let’s notice that the question asks us to give our answer in units of square centimeters. We can recall that one meter is equal to 100 centimeters. Then, taking the square of both sides of this, we find that one square meter is equal to 10000 square centimeters. So, to convert an area from units of meters squared into units of centimeters squared, we need to multiply the value by a factor of 10000.

We have then that the area 𝐴 is equal to 0.001 multiplied by 10000 centimeters squared. This works out as 10 centimeters squared. So our answer to this question is that the area of the part of the foot on which the dancer stands is equal to 10 square centimeters.

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