Question Video: Finding the Maclaurin Series of an Exponential Function | Nagwa Question Video: Finding the Maclaurin Series of an Exponential Function | Nagwa

Question Video: Finding the Maclaurin Series of an Exponential Function Mathematics

Find the Maclaurin series of the function 𝑓(𝑥) = 𝑒^𝑥.

02:03

Video Transcript

Find the Maclaurin series of the function 𝑓 of 𝑥 equals 𝑒 to the power of 𝑥.

We recall that the Maclaurin series of a function 𝑓 of 𝑥 is given by the sum of the 𝑛th derivative of 𝑓 evaluated at zero over 𝑛 factorial times 𝑥 to the 𝑛th power for values of 𝑛 between zero and ∞. So we’ll begin by differentiating 𝑓 of 𝑥 to evaluate 𝑓 prime of zero, 𝑓 double prime of zero, and so on. Ultimately, we’re hoping to find what the 𝑛th derivative of our function is at 𝑥 equals zero. We know that 𝑓 of 𝑥 is equal to 𝑒 to the power of 𝑥. The derivative of 𝑒 to the power of 𝑥 is simply 𝑒 to the power of 𝑥. So we find that 𝑓 prime of 𝑥 is 𝑒 to the power of 𝑥. 𝑓 double prime of 𝑥 is the derivative of this, which is also 𝑒 to the power of 𝑥. And we can continue this. And we’ll see that the 𝑛th derivative of 𝑓 will also be equal to 𝑒 to the power of 𝑥.

We need to work out what 𝑓 of zero, 𝑓 prime of zero, and so on is. So 𝑓 of zero is 𝑒 to the power of zero, which is one. 𝑓 prime of zero is also 𝑒 to the power of zero, which is one. And since we know that the 𝑛th derivative of 𝑓 at 𝑥 is 𝑒 to the power of 𝑥, we know that the 𝑛th derivative of 𝑓 at zero is 𝑒 to the power of zero, which is one. We therefore replace the 𝑛th derivative of 𝑓 evaluated at zero with one. And we find that our summand is one over 𝑛 factorial times 𝑥 to the 𝑛th power. We can, of course, simplify this to 𝑥 to the 𝑛th power over 𝑛 factorial. And so we see that the Maclaurin series of the function 𝑓 of 𝑥 equals 𝑒 to the power of 𝑥 is the sum from 𝑛 equals zero to ∞ of 𝑥 to the 𝑛th power over 𝑛 factorial. And this is one plus 𝑥 plus 𝑥 squared over two factorial plus 𝑥 cubed over three factorial and so on.

So what about the radius of convergence of this series? We recall that if a series converges on the open interval from negative 𝑅 to 𝑅, its radius of convergence is the number denoted by 𝑅. And of course, a power series always converges absolutely within its radius of convergence. Similarly, the interval of convergence is the open, closed, or semiclosed range of values of 𝑥, for which the Maclaurin series converges to the value of the function.

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