Question Video: Calculating Atom Economy for a Complex Reaction Equation | Nagwa Question Video: Calculating Atom Economy for a Complex Reaction Equation | Nagwa

Question Video: Calculating Atom Economy for a Complex Reaction Equation Chemistry

Calcium metal can be used to produce pure rubidium from its chloride according to the equation: Ca (s) + 2RbCl (s) ⟶ CaCl₂ (s) + 2Rb (l). What is the atom economy for the production of rubidium by this process, to the nearest percentage unit?

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Video Transcript

Calcium metal can be used to produce pure rubidium from its chloride according to the equation: Ca solid plus two RbCl solid reacting to give CaCl2 solid plus two Rb liquid. What is the atom economy for the production of rubidium by this process, to the nearest percentage unit?

This question asks us to determine the atom economy for the production of rubidium. Atom economy is a measure of the amount of starting materials or reactants which are converted to useful or desirable products. The expression or equation for atom economy can be expressed in several different ways. One way is to say atom economy is equal to the total relative formula mass of the desired or useful product or products divided by the total relative formula mass of all the reactants. And we can multiply by 100 percent to get the answer in terms of a percentage.

So first we need to determine the total relative formula mass of the desired product. And in this example, the desired product is Rb or rubidium. When we calculate the value for the numerator, we will need to take into account the coefficient of two in front of rubidium. We will also need to calculate the total relative formula mass of all the reactants. And the reactants are Ca or calcium and RbCl, which is rubidium chloride. Again, we will need to take into consideration the stoichiometric coefficient of two in front of rubidium chloride.

Let’s clear some space to do the calculations for the relative formula masses of the substances in the numerator and in the denominator. So let’s start by calculating the relative formula mass of the desired product rubidium. Taking into account the coefficient of two, we can put in the relative formula mass — in this case, just the relative atomic mass — of rubidium, which is 85.468. And we get this from the periodic table. We get a value of 170.936, and this is unitless.

Let’s now do the same calculation for both of the reactants, calcium and rubidium chloride. Calcium has a mass value of 40.078 from the periodic table. And for rubidium chloride, we will multiply the values by two because of the coefficient two. Rubidium’s mass value is 85.468, and chlorine, 35.45 from the periodic table. When we solve, we get 241.836. Now we can use the atom economy expression and plug in our values into the numerator and denominator.

The total relative formula mass of the desired product rubidium is 170.936. So we put this in the numerator. And the total relative formula mass of all the reactants will be the sum of the relative formula mass of each reactant, calcium and rubidium chloride, whose mass values we have calculated. Adding the two denominator values, we get a total value of 281.914. Taking the numerator divided by the denominator, we get an answer of 60.6 percent, which is the atom economy for the production of rubidium by this process.

However, the question asks us to express the answer to the nearest percentage unit. So rounding up, we get an answer of 61 percent. What does this answer mean? The answer tells us that 61 percent of the starting materials ended up as the useful desired target product, rubidium. Finally, the atom economy for the production of rubidium by the process given in the equation is 61 percent.

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