Question Video: Finding the Unknown Force in a Group of Forces Acting on a Body Moving with Constant Velocity | Nagwa Question Video: Finding the Unknown Force in a Group of Forces Acting on a Body Moving with Constant Velocity | Nagwa

Question Video: Finding the Unknown Force in a Group of Forces Acting on a Body Moving with Constant Velocity Mathematics

In the figure, the body is moving at a constant velocity 𝑣 under the action of a system of forces. Given that the forces are measured in newtons, find the magnitudes of 𝐹 and 𝑘.

02:59

Video Transcript

In the figure, the body is moving at a constant velocity 𝑣 under the action of a system of forces. Given that the forces are measured in newtons, find the magnitudes of 𝐹 and 𝑘.

We’re told that this body is moving at a constant velocity under a number of forces. And so, we’re able to recall Newton’s first law of motion. This says that if there’s no net force, in other words, the forces acting on the body cancel each other out, the object will maintain a constant velocity. So, for our body to maintain its constant velocity under the action of the system of forces, we need the sum of these forces to be equal to zero. Now, in fact, our forces are acting in two dimensions. So, we could consider the horizontal and vertical directions separately or think about it as a vector such that the vector sum of the forces is equal to zero.

We’re going to think about this as two directions, and we’re going to consider the vertical direction first. We’ll take upwards to be positive. Now, it doesn’t really matter which direction we choose to be positive as long as we’re consistent throughout the question. The only force that we have acting in that direction is force 𝐹. If we look carefully, we see that the force that’s parallel to 𝐹 is 20, and that’s acting in the opposite direction. So, the sum of these two forces must be 𝐹 minus 20.

We also have a force of 31 newtons acting in the negative direction. So, the sum of all of our forces acting vertically is 𝐹 minus 20 minus 31. And of course, we know that this must be equal to zero for our object to maintain a constant velocity. So let’s simplify the expression. Negative 20 minus 31 becomes negative 51. So, the sum of our forces is 𝐹 minus 51. And our equation is 𝐹 minus 51 equals zero. To solve this equation, to find the value of 𝐹, we’re simply going to add 51 to both sides. And when we do, we find 𝐹 is equal to 51. We were told that the forces are measured in newtons. So, we can say 𝐹 must itself be 51 newtons.

We’re now going to repeat this process in the horizontal direction. This time moving to the right is our positive direction. The force given by the arrow acting in this direction is 𝑘 newtons. Then, in the opposite direction, we have 79 newtons. So, the sum of the forces acting on this body in our horizontal direction is 𝑘 minus 79. Once again, we can set this equal to zero because we’re told that the object has a constant velocity. Then, we solve for 𝑘. And we add 79 to both sides. And when we do, we find 𝑘 is equal to 79 or 79 newtons. 𝐹 is, therefore, equal to 51 newtons and 𝑘 is equal to 79 newtons.

Join Nagwa Classes

Attend live sessions on Nagwa Classes to boost your learning with guidance and advice from an expert teacher!

  • Interactive Sessions
  • Chat & Messaging
  • Realistic Exam Questions

Nagwa uses cookies to ensure you get the best experience on our website. Learn more about our Privacy Policy