Question Video: Calculating the Current Carried by a Circular Loop | Nagwa Question Video: Calculating the Current Carried by a Circular Loop | Nagwa

Question Video: Calculating the Current Carried by a Circular Loop Physics • Third Year of Secondary School

A circular loop of wire with a radius of 9.5 cm carries a constant current of 𝐼 A. The strength of the magnetic field produced by the current is 5.2 × 10⁻⁵ T at the center of the loop. Calculate 𝐼, rounding your answer to 1 decimal place. Use a value of 4𝜋 × 10⁻⁷ T.m/A for 𝜇₀.

02:16

Video Transcript

A circular loop of wire with a radius of 9.5 centimeters carries a constant current of 𝐼 amperes. The strength of the magnetic field produced by the current is 5.2 times 10 to the negative fifth teslas at the center of the loop. Calculate 𝐼, rounding your answer to one decimal place. Use the value of four 𝜋 times 10 to the negative seventh tesla meters per ampere for 𝜇 nought.

So here, we have a circular loop of wire with a radius we’ve called 𝑟 given as 9.5 centimeters. And we’re told that the loop carries a constant current of 𝐼 amperes. So 𝐼 is some pure number. And this is a current value expressed in amperes. Due to this current, a magnetic field is produced at the center of this circular loop. If we call the magnitude of that field 𝐵, we’re told that it’s equal to 5.2 times 10 to the negative fifth teslas.

Knowing all this, we want to calculate the magnitude of the current 𝐼. To do this, we can recall that the magnetic field magnitude at the center of a current-carrying circular loop is equal to this constant 𝜇 nought, the permeability of free space, multiplied by the current magnitude in the loop divided by two times the loop’s radius. Now, in our statement, we’re given 𝜇 nought, we’re given 𝑟, and we’re also given 𝐵, wanting to solve for the current 𝐼.

Now, if we multiply both sides of this expression by two 𝑟 divided by 𝜇 nought, then over on the right-hand side, the factors of two cancel and the factors of 𝑟 and 𝜇 nought, leaving us just with the current 𝐼. So two times 𝑟 times 𝐵 over 𝜇 nought equals 𝐼. And if we substitute in the values we’re given for 𝐵, 𝑟, and 𝜇 nought, then we come up with this expression here.

We’re just about ready to calculate 𝐼. But before we do, let’s change the units of our radius, which are in centimeters, so that they match the SI base units in the rest of our expression. In other words, let’s convert our radius from centimeters into meters. 9.5 centimeters is 0.095 meters. So now, when we go ahead and calculate 𝐼, to one decimal place, we find a result of 7.9 amperes.

For our final answer, though, we’ll just box the number portion of this quantity because recall that our problem statement tells us we have a constant current of 𝐼 amperes. So to solve for 𝐼, we just want a number. And that result is 7.9.

Join Nagwa Classes

Attend live sessions on Nagwa Classes to boost your learning with guidance and advice from an expert teacher!

  • Interactive Sessions
  • Chat & Messaging
  • Realistic Exam Questions

Nagwa uses cookies to ensure you get the best experience on our website. Learn more about our Privacy Policy