Question Video: Using the Properties of Definite Integration of an Odd Function to Evaluate an Integral | Nagwa Question Video: Using the Properties of Definite Integration of an Odd Function to Evaluate an Integral | Nagwa

Question Video: Using the Properties of Definite Integration of an Odd Function to Evaluate an Integral Mathematics • Third Year of Secondary School

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Determine ∫_(−1)^(1) ((9𝑥³ − 6𝑥)/(2𝑥² + 9)) d𝑥.

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Video Transcript

Determine the definite integral from negative one to one of nine 𝑥 cubed minus six 𝑥 all over two 𝑥 squared plus nine with respect to 𝑥.

In this question, we are asked to evaluate the definite integral of a rational function. We could do this by attempting to find an antiderivative. However, it is often possible to simplify definite integrals by using the properties of integration. We can evaluate this definite integral by recalling that the definite integral from negative 𝑎 to 𝑎 of an odd function 𝑓 of 𝑥 with respect to 𝑥 is zero for any constant 𝑎.

The reason that this result holds true is that the graphs of odd functions have rotational symmetry of 180 degrees about the origin. So the area under the curve to the left and right of zero for an equal distance will be the same.

This is a useful result in this case because the given integrand is an odd function. We can show this in many ways. For instance, we can recall that we say a function is odd if 𝑓 of negative 𝑥 equals negative 𝑓 of 𝑥 for any value of 𝑥 in the domain of 𝑓. We can then note that the numerator of the integrand is a polynomial containing only odd powers. We can recall that this means that the numerator is an odd function. Similarly, we can see that the denominator is a polynomial only containing even powers of 𝑥. We can recall that this means that it is an even function.

Finally, we know that the quotient of an odd and even function is odd, so the integrand is odd. We can also show that the integrand is odd more directly by substituting negative 𝑥 into the function to obtain the following expression. We then see that the even powers will lose the power of negative one and the odd powers will retain this factor.

We can then take out the factor of negative one in the numerator and simplify the denominator to obtain the following expression. We see that this is equivalent to negative 𝑓 of 𝑥. Hence, the integrand is odd. Since we have shown that the integrand is odd, we can apply this property to conclude that the definite integral from negative one to one of nine 𝑥 cubed minus six 𝑥 all divided by two 𝑥 squared plus nine is zero.

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