### Video Transcript

In this video, we will learn how to
determine if a series is absolutely convergent, conditionally convergent, or
divergent.

We know that if a series is called
convergent, it means that the partial sums approach a specific limit. But what does it mean for a series
to be called absolutely convergent? We say a series is called
absolutely convergent if the series of absolute values is convergent. One thing to notice is that if π
π is a series with positive terms, then the absolute value of π π is equal to π
π. So absolute convergence implies
convergence.

First, letβs look at an example
where we have to determine whether a series is absolutely convergent.

Is the series the sum from π
equals one to β of negative one to the power of π add one over π squared
absolutely convergent?

Remember to test for absolute
convergence, we need to check whether the series of absolute values is convergent,
in other words, is the sum from π equals one to β of the absolute value of negative
one to the power of π add one over π squared convergent. First of all, notice that negative
one to the power of π add one is always going to be either one or negative one,
depending on whether the power is even or odd. So if we take the absolute value of
negative one raised to the power of π add one, this is always going to be one. We know the π runs from one to
β. So π squared is always going to be
positive. So we can actually rewrite this as
one over π squared.

Remember that weβre trying to
determine whether this converges or diverges. But we actually recognize the sum
from π equals one to β of one over π squared to be a series that we know. Itβs a π-series. So we use the fact that a π-series
converges if π is greater than one and diverges if π is less than or equal to
one. So for our question, we see that
this is a π-series with π equal to two. Because this is greater than one,
we can say that the sum from π equals one to β of one over π squared is
convergent. So because we found the series of
absolute values to be convergent, then the series is absolutely convergent.

Interestingly, if we find a series,
which is not absolutely convergent, it may still be convergent. We call this conditional
convergence. A series is conditionally
convergent if the series is convergent but not absolutely convergent. In other words, the sum from π
equals one to β of the absolute value of π π diverges. But the sum from π equals one to β
of π π converges. And if a series is not absolutely
convergent and itβs not conditionally convergent, then itβs divergent.

Letβs see an example of conditional
convergence.

Is the alternating harmonic series
the sum from π equals one to β of negative one to the power of π add one
multiplied by one over π absolutely convergent, conditionally convergent, or
divergent?

Letβs firstly remember that a
series is absolutely convergent if the series of absolute values is convergent. And a series is conditionally
convergent if the series of absolute values diverges but the series converges. And otherwise, the series is
divergent. So letβs start by testing for
absolute convergence. We can see that negative one raised
to the power of π add one is always going to give us one when we take the absolute
value. So this is in fact the same as the
sum from π equals one to β of one over π. But this is actually a series that
weβre familiar with. Itβs the harmonic series. And we know that the harmonic
series diverges. So the alternating harmonic series
is not absolutely convergent. But is it conditionally convergent
or divergent?

So our next step is to test the
alternating harmonic series for convergence. Because thatβs an alternating
series, we can do this with the alternating series test. Recall this says that for an
alternating series, the sum of negative one to the power of π add one multiplied by
π π if π π is decreasing and the limit as π approaches β of π π is equal to
zero, then π π is convergent. So for the alternating harmonic
series, we can say that π π equals one over π. So is π π decreasing? Well, as π increases, one over π
does decrease. So that condition is satisfied. But does the limit as π approaches
β of π π equal zero? Well, the limit as π approaches β
of one over π is going to be one over β, which we know is zero. So that condition is satisfied. So because we found that the
alternating harmonic series is not absolutely convergent, but it is convergent, we
can conclude that the alternating harmonic series is conditionally convergent.

We can summarize the check for
absolute convergence, conditional convergence, and divergence in a helpful
diagram. Letβs say we want to find out
whether the series π π is absolutely convergent, conditionally convergent, or
divergent. We begin by testing whether the
series of absolute values is convergent or divergent. Letβs say that we find that the
series of absolute values is convergent. Then, the series π π is
absolutely convergent. But if we find that the series of
absolute values is divergent, then the series π π is not absolutely
convergent. But it may still be conditionally
convergent. So we try a different test on the
series π π to check for convergence, for example, the alternating series test.

And if we find that the series π
π converges, then we say that the series π π is conditionally convergent. But if we find that the series π
π diverges, then we conclude that the series π π is divergent. So these are the three possible
conclusions that we can draw.

So letβs now see some more
examples.

Consider the series the sum from π
equals one to β of sin of π over π cubed. Determine whether the series is
absolutely convergent, conditionally convergent, or divergent.

Recall that a series π π is
absolutely convergent if the series of absolute values is convergent. And if we find that the series is
not absolutely convergent, it may still be conditionally convergent. So we then test the series for
convergence or divergence. So letβs begin by testing this
series for absolute convergence. So we want to find out whether the
sum from π equals one to β of the absolute value of sin of π over π cubed is
convergent or divergent.

Well, because π only runs through
positive values from one to β, π cubed is always going to be positive. So this is just the sum from π
equals one to β of the absolute value of sin of π over π cubed. Now we know that sin of π will
always be between negative one and one. So we can say that the absolute
value of sin of π will always be less than or equal to one, which means that we can
write the absolute value of sin of π over π cubed is less than or equal to one
over π cubed. Writing it this way allows us to do
a direct comparison. Recall that this means if π π is
less than π π and the sum from π equals one to β of π π converges, then the sum
from π equals one to β of π π also converges.

And one over π cubed is actually a
series we recognize. Recall that a π-series is a series
of the form the sum for π equals one to β of one over π to the π power. And this converges if π is greater
than one and diverges if π is less than or equal to one. So one over π cubed is a π-series
with π equal to three. So one over π cubed converges. So by direct comparison, the
absolute value of sin of π over π cubed also converges. Then, because we found the series
of absolute values to be convergent, then our series the sum from π equals one to β
of sin of π over π cubed is absolutely convergent.

State whether the series the sum
from π equals one to β of negative one to the power of π add one multiplied by two
over the square root of π add one converges absolutely, conditionally, or not at
all.

Firstly, recall that for a series
π π, this is absolutely convergent if the series of absolute values converges. And itβs conditionally convergent
if the series of absolute values diverges. But the series itself
converges. So letβs first of all find out
whether this series is absolutely convergent or not. This means testing whether the
series from π equals one to β of the absolute value of negative one to the power of
π add one multiplied by two over the square root of π add one is convergent or
divergent.

Well, negative one to the power of
π add one is always going to be one or negative one. But if we take the absolute value,
it will always be one. Whereas two over the square root of
π add one will always be positive because π runs through positive values. So we can write this as the sum
from π equals one to β of two over the square root of π add one. Then, we can use the constant
multiplication rule to bring the two to the front of the sum. From here, we need to work out
whether this series converges or diverges. One way we can actually do this is
with a direct comparison with the harmonic series.

Because for π is greater than two,
we have that one over π is less than one over the square root of π add one. And we know that if we have π π
less than π π where π π diverges, then π π also diverges. And we know that the sum from π
equals one to β of one over π is the harmonic series which diverges. Then, the sum from π equals one to
β of one over the square root of π add one also diverges. So we found that the series of
absolute values diverges, which means that this series is not absolutely
convergent. But it could still be conditionally
convergent. So weβre going to test the series
itself for convergence. So letβs clear some space.

We can firstly bring the constant
two to the front of the sum. And then, if we look at this
negative one to the power of π add one, this creates an alternating series because
it makes the terms alternate between positive and negative. So we can decide whether this
series is convergent or divergent using the alternating series test. Remember that this says for a
series π π, where π π is equal to negative one to the power of π add one
multiplied by π π, if π π is decreasing and the limit as π approaches β of π
π is equal to zero, then the series π π is convergent. So for our series π π is equal to
one over the square root of π add one. But is this decreasing? Well, for π π to be decreasing,
we need π π to be greater than π π add one.

Well, we can see that as π
increases by one, the square root of π add one is going to get bigger. So one over the square root of π
add one is going to decrease. So π π is decreasing. Then, we need to check whether the
limit as π approaches β of π π is equal to zero. In other words, is the limit as π
approaches β of one over the square root of π add one zero? Well, the square root of π add one
is increasing as π gets bigger. So this will be one over β. So as π approaches β, then one
over the square root of π add one approaches one over β. And so the limit as π approaches β
is zero. So both of these conditions are
satisfied. So this series is convergent.

Remember that we said that a series
is conditionally convergent if the series of absolute values diverges but the series
converges. And thatβs exactly what weβve found
here. The series of absolute values was
divergent. But we found the series itself to
be convergent. So we can conclude that this series
converges conditionally.

But why is that helpful to
differentiate between absolutely convergent and conditionally convergent series? Well, absolutely convergent
infinite series holds some of the same properties as finite sums. For example, if we have a finite
sum, then any rearrangement of the terms still gives the same sum. And this also holds true for an
absolutely convergent series. Any rearrangement yields the same
sum. But this is not true for a
conditionally convergent series. This is because rearranging the
terms of a series changes the partial sums. So this can change the limit of the
partial sums when some of the terms are negative. So we donβt have that issue with
absolutely convergent series. But of course, this doesnβt apply
to conditionally convergent series.

As an example, the alternating
harmonic series, which weβve seen is convergent, can be shown to converge to the
natural log of two. But if the terms in the series are
rearranged so that every positive term is followed by two negative terms, this does
change the value of the sum. So with a conditionally convergent
series, rearrangement changes the relative rate at which positive and negative terms
are used and in turn changes the sum of the series. In fact, we can actually use this
to rearrange a conditionally convergent series to converge to any value we want. But itβs beyond the scope of this
video to go through these proofs in detail.

Letβs now summarize some of the
main points. A series π π is absolutely
convergent if the series of absolute values is convergent. And a series π π is conditionally
convergent if the series of absolute values is divergent, but the series itself is
convergent. And finally, if π π is an
absolutely convergent series with sum π , then any rearrangement of π π yields the
same sum π .