Question Video: Finding the Solution Set to an Equation over the Set of Real Numbers | Nagwa Question Video: Finding the Solution Set to an Equation over the Set of Real Numbers | Nagwa

Question Video: Finding the Solution Set to an Equation over the Set of Real Numbers Mathematics

Find, in ℝ, the solution set of the equation 3√(3) π‘₯ + 1 = √(3) π‘₯ + 4.

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Video Transcript

Find, in the set of real numbers, the solution set of the equation three root three π‘₯ plus one is equal to root three π‘₯ plus four.

In this question, we’re given an equation in a variable π‘₯ and asked to find the solution set of this equation in the set of real numbers.

To do this, we can start by recalling that the solution set of the equation in the set of real numbers means the set of all real values that satisfy the given equation. Since both sides of the equation are equal, we can apply the same operations to both sides of the equation and they will remain equal. We can use this to isolate π‘₯ on one side of the equation.

We can begin by subtracting one from both sides of the equation. On the left-hand side of the equation, we have one minus one is zero. And on the right-hand side of the equation, we have four minus one is three. So, we obtain three root three π‘₯ equals root three π‘₯ plus three.

Since we want to isolate π‘₯ on one side of the equation, we now need to subtract root three π‘₯ from both sides of the equation. This gives us that three root three π‘₯ minus root three π‘₯ is equal to three. To isolate π‘₯ on the left-hand side of the equation, we can take out the shared factor of π‘₯ from both terms. This gives us that three root three minus root three times π‘₯ equals three.

We can then note that three root three minus root three is equal to two root three. This gives us the equation two root three π‘₯ equals three. To isolate the variable π‘₯ on the left-hand side of the equation, we need to divide both sides of the equation by two root three. This gives us that π‘₯ must be equal to three divided by two root three. This is the only solution to this equation; however, we should rationalize the denominator to write our answer in a standard form.

We rationalize the denominator by multiplying both the numerator and denominator by the square root of three. This is equivalent to multiplying by one, so it does not affect the solution. In the denominator, we can note that root three times root three is three. So, we have three root three over two times three. We can then cancel the shared factor of three in the numerator and denominator to see that the only solution is π‘₯ equals root three over two.

Remember though we are asked to find the solution set of the equation over the set of real numbers. So, we need to give our answer as a set and check that the answers are real numbers. In this case, we know that root three over two is a real number. So, the solution set of the given equation over the set of real numbers is the set containing only the value root three over two.

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