Question Video: Calculating the Work Done by a Force | Nagwa Question Video: Calculating the Work Done by a Force | Nagwa

Question Video: Calculating the Work Done by a Force Physics • First Year of Secondary School

A constant force pushes an object for 25 m, as shown in the diagram. How much work is done by the force?

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Video Transcript

A constant force pushes an object for 25 meters, as shown in the diagram. How much work is done by the force?

Okay, so in this question, weโ€™re given a diagram that shows a 5.2-newton force acting on an object. The question tells us that this force is constant, which means that it keeps the same value of 5.2 newtons. Letโ€™s label this force as ๐น. We can see from the diagram that ๐น acts to the right, and so this force causes the object to move to the right. We are told that it moves a distance of 25 meters, and this is also shown in the diagram. Letโ€™s label this distance moved by the object as ๐‘‘.

Weโ€™re being asked to find how much work is done by the force. We can recall that the work done on an object by a force is equal to the magnitude of the force multiplied by the distance the object moves. If we label the work done as ๐‘Š, then for a force ๐น which causes an object to move a distance ๐‘‘, we can write this equation in terms of symbols as ๐‘Š is equal to ๐น multiplied by ๐‘‘. In this case, we know the value of the force ๐น and we know the distance ๐‘‘ that the object moves. So letโ€™s go ahead and sub those values into this equation to calculate the work done ๐‘Š. When we do this, we get that ๐‘Š is equal to 5.2 newtons, thatโ€™s the value for ๐น, multiplied by 25 meters, the value for ๐‘‘.

At this point, we should notice that the force is given in its SI unit of newtons. And the distance is in units of meters, the SI base unit for distance. A force in newtons and a distance in meters means that weโ€™ll calculate a work done in the SI unit of energy, the joule. Evaluating this expression gives us a result of 130 joules. So our answer to this question is that the amount of work done by the force is 130 joules.

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