Question Video: Comparing the Change in the Weight of an Object Due to a Change in Acceleration Due to Gravity | Nagwa Question Video: Comparing the Change in the Weight of an Object Due to a Change in Acceleration Due to Gravity | Nagwa

Question Video: Comparing the Change in the Weight of an Object Due to a Change in Acceleration Due to Gravity Physics • First Year of Secondary School

If the acceleration due to gravity on Mars is 3/8 the acceleration due to gravity on Earth, what is the weight of an object on Mars if it weighs 184 N on Earth?

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Video Transcript

If the acceleration due to gravity on Mars is three-eighths the acceleration due to gravity on Earth, what is the weight of an object on Mars if it weighs 184 newtons on Earth?

This question is asking us to calculate the weight of an object on Mars given its weight on Earth. Recall that the weight of an object is equal to the mass of the object multiplied by the acceleration due to gravity experienced by the object. The value of the acceleration due to gravity is different on different planets because it depends on the planet’s size and mass. This means an object with a particular mass will have a different weight on Mars than it does on Earth.

Let’s call the acceleration due to gravity of Earth 𝑔 sub Earth. This means that the weight of an object on Earth, which we’ll call π‘Š sub Earth, is equal to π‘š times 𝑔 sub Earth. Similarly, we can call the acceleration due to gravity on Mars, 𝑔 sub Mars. The weight of an object on Mars is equal to π‘š times 𝑔 sub Mars. We’re told that the acceleration due to gravity on Mars is three-eighths the acceleration due to gravity on Earth. Mathematically, we can write this as 𝑔 sub Mars equals three-eighths times 𝑔 sub Earth.

Let’s substitute this expression for 𝑔 sub Mars into the formula for the weight of an object on Mars. We see that π‘š times 𝑔 sub Mars is equal to π‘š times three-eighths times 𝑔 sub Earth. Rewriting this expression slightly, we can see that the weight of an object on Mars is equal to three-eighths times π‘š times 𝑔 sub Earth.

Now, we notice something very interesting in this formula. These last two terms here, π‘š times 𝑔 sub Earth, actually equal the weight of an object on Earth. We are told that the weight of the object on Earth is equal to 184 newtons. Substituting this in, we see that the weight of the object on Mars is equal to three-eighths times 184 newtons. Completing this calculation gives us a value of 69 newtons.

So the weight of the object on Mars is equal to 69 newtons if it weighs 184 newtons on Earth.

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