Question Video: Expanding the Product of Three Binomials | Nagwa Question Video: Expanding the Product of Three Binomials | Nagwa

Question Video: Expanding the Product of Three Binomials Mathematics • First Year of Preparatory School

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Expand the expression (5𝑥 + 2𝑦)(𝑦 − 2𝑥)², giving your answer in its simplest form.

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Video Transcript

Expand the expression five 𝑥 plus two 𝑦 times 𝑦 minus two 𝑥 squared, giving your answer in its simplest form.

We want to expand and simplify this expression. We can do this by first expanding the square of the binomial 𝑦 minus two 𝑥. First of all, we must write 𝑦 minus two 𝑥 squared as the product of 𝑦 minus two 𝑥 and 𝑦 minus two 𝑥. We can then distribute the first binomial over each term in the second binomial. Then we have 𝑦 times 𝑦 minus two 𝑥 minus two 𝑥 times 𝑦 minus two 𝑥.

We can then distribute each product to obtain the following products. For the first term, we have 𝑦 times 𝑦 plus negative two 𝑥 times 𝑦. In the second term, we have 𝑦 times negative two 𝑥 plus negative two 𝑥 times negative two 𝑥.

For the next step, we will be using the product rule for exponents, which states that for any positive integers 𝑚 and 𝑛, we have 𝑥 to the power of 𝑚 times 𝑥 to the power of 𝑛 equals 𝑥 to the power of 𝑚 plus 𝑛. Using the product rule, we simplify each term as follows. We can now combine like terms to get 𝑦 squared minus four 𝑥 𝑦 plus four 𝑥 squared. We can substitute this into the original expression to obtain five 𝑥 plus two 𝑦 times 𝑦 minus two 𝑥 squared is equal to five 𝑥 plus two 𝑦 times 𝑦 squared minus four 𝑥𝑦 plus four 𝑥 squared.

Now we will clear part of our work to make space for the next multiplication. We can now follow the same process to distribute the factor of five 𝑥 plus two 𝑦 over the trinomial. First, we distribute the binomial over every term in the trinomial, like so. Second, we distribute each monomial over the binomials. So we have 𝑦 squared times five 𝑥 plus 𝑦 squared times two 𝑦 plus negative four 𝑥𝑦 times five 𝑥 plus negative four 𝑥𝑦 times two 𝑦 plus four 𝑥 squared times five 𝑥 plus four 𝑥 squared times two 𝑦.

We can now simplify each term using the commutative property of multiplication and the product rule for exponents. So we have five 𝑥𝑦 squared plus two 𝑦 cubed minus 20𝑥 squared 𝑦 minus eight 𝑥𝑦 squared plus 20𝑥 cubed plus eight 𝑥 squared 𝑦.

Finally, we rearrange and combine like terms to get negative three 𝑥𝑦 squared plus two 𝑦 cubed minus 12𝑥 squared 𝑦 plus 20𝑥 cubed. Rearranging the terms to be in standard form order with respect to 𝑥 gives 20𝑥 cubed minus 12𝑥 squared 𝑦 minus three 𝑥𝑦 squared plus two 𝑦 cubed.

In conclusion, we have shown that five 𝑥 plus two 𝑦 times 𝑦 minus two 𝑥 squared simplifies to 20𝑥 cubed minus 12𝑥 squared 𝑦 minus three 𝑥𝑦 squared plus two 𝑦 cubed.

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