### Video Transcript

Given that the two polygons are
similar, find the value of π₯.

When dealing with any question
involving similar polygons, we know that the corresponding angles are congruent or
the same and the corresponding sides are proportional. One pair of corresponding sides are
π½π and π
π. A second pair of corresponding
sides are πΆπ½ and ππ
. As the corresponding sides are
proportional, we know that their ratios are the same. Two π₯ plus six over seven π₯ minus
seven must be equal to 24 over 28.

In order to find the value of π₯,
we could cross multiply at this stage. However, it is easier to simplify
our fractions first. We can factor the numerator and
denominator of the left-hand fraction. Two π₯ plus six becomes two
multiplied by π₯ plus three. And seven π₯ minus seven becomes
seven multiplied by π₯ minus one. Dividing the numerator and
denominator of our right-hand fraction by four gives us six over seven as 24 divided
by four is six and 28 divided by four is equal to seven.

The denominators on both sides are
divisible by seven. And the numerators are divisible by
two. This leaves us with a simplified
equation of π₯ plus three over π₯ minus one is equal to three. We can multiply both sides of this
equation by π₯ minus one. Distributing the parentheses gives
us π₯ plus three is equal to three π₯ minus three. We can then subtract π₯ and add
three to both sides of the equation. This gives us six is equal to two
π₯. Finally, dividing both sides by two
gives us π₯ is equal to three.

If the two polygons are similar,
the value of π₯ is three. We can check this by substituting
three back into the expressions for the smaller shape. Two multiplied by three is equal to
six, and adding six to this gives us 12. Seven multiplied by three is equal
to 21 and subtracting seven gives us 14. It is therefore clear that our two
polygons are similar with a scale factor of two as 12 multiplied by two is 24 and 14
multiplied by two is 28.