### Video Transcript

π΄π΅πΆπ· is a parallelogram. π΄ is the point negative one, one. π΅ is the point four, one. And π· is the point negative three, negative three. Part a), draw π΄π΅πΆπ· on the centimetre grid below. Part b), work out the area of π΄π΅πΆπ·.

So, the first thing we need to do in this question to answer part a is plot the three points that weβve been given. So, Iβm gonna plot point π΄, which is negative one, one, remembering that the first number is the π₯-coordinate and the second number is the π¦-coordinate. But we can also think of it is along the corridor and up the stairs.

So, Iβve plotted point π΄. So, itβs negative one on the π₯-axis and one on the π¦-axis. Now, I need to plot point π΅, which is four, one. And as you can see for point π΅, weβve gone along the π₯-axis four and up the π¦-axis one. So, thatβs point π΅ plotted. And then, we have point π·. And Point π· is at negative three, negative three. So, Iβve plotted that on the graph as well. So, now, how do we plot point πΆ? Well, we need to find out what this is.

Well to help us, what Iβm gonna do is join the other points first. So, now, to help us plot point πΆ, we have to think of a couple of properties of a parallelogram. First of all, opposite sides are parallel. And also, opposite sides are of equal length. So therefore, we can see that π΄π΅ is five units long. So therefore, π·πΆ must also be five units long. But also, π΄π΅ must be parallel to π·πΆ. So therefore, if π΄π΅ is a horizontal line, π·πΆ must also be a horizontal line. So, Iβve drawn our horizontal line π·πΆ. Itβs five units long and its horizontal. So, now, I can mark our point πΆ.

So, now, Iβve completed parallelogram π΄π΅πΆπ·, and drawn it on our centimetre grid below. And we can see that itβs correct because weβve got two pairs of parallel sides. The sides are also equal length when they are opposite. Okay, now, letβs move on to part b.

In part b, what we need to do is work out the area of π΄π΅πΆπ·. So, to work out the area of π΄π΅πΆπ·, we need to use this formula we know. And that is that the area of a parallelogram is equal to the base multiplied by the perpendicular height. And just reminding ourselves, perpendicular means at right angles to. And the reason we say this is because it is not the slope height. So, for instance, it is not one of our sloped sides.

And often in parallelogram questions, they give you the length of this side as a bit of a red herring because people will make the mistake of using it when calculating the area. Because, as we said, the perpendicular height is the height for our parallelogram that is at right angles to either one of the horizontal edges. So, weβve got that there.

And we can see that the perpendicular height is four units. And weβve also got the base length because we worked that out earlier. That is five units. So therefore, the area is gonna be equal to five, which is our base length, multiplied by four, our perpendicular height, which is gonna give us 20. And weβre told that itβs on a centimetre grid. So therefore, we can add units. And we can say that the area of π΄π΅πΆπ· is 20 centimetres squared.

And just to explain why we can use this formula, what Iβve done is Iβve drawn some orange dashed lines here. Because this shows what would happen if we straightened up our parallelogram. Because if we straightened up our parallelogram, it would turn into a rectangle. And a rectangle would have a height of four and a length of five. We know for a rectangle you just multiply length by height, or length by width. So therefore, thatβs why we can use that formula to work out the area of a parallelogram.