Question Video: Constructing the Equation for the Solubility Product of Vanadium(III) Carbonate | Nagwa Question Video: Constructing the Equation for the Solubility Product of Vanadium(III) Carbonate | Nagwa

Question Video: Constructing the Equation for the Solubility Product of Vanadium(III) Carbonate Chemistry • Third Year of Secondary School

What is the equation for the solubility product of vanadium(III) carbonate (V₂(CO₃)₃)?

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Video Transcript

What is the equation for the solubility product of vanadium(III) carbonate, V2(CO3)3?

This question is asking us to determine the equation for the solubility product of the compound given. The solubility product, or K sp, is the product of the concentrations of the ions in a saturated solution raised to the power of their respective stoichiometric coefficients. For example, a generic insoluble solid can be represented with the formula MA. Even if it is considered insoluble, a compound likely exists in equilibrium with water and some slight dissolution occurs. We can express this dissolution with M1+ and A1− ions as aqueous products.

In this generic equation, lowercase 𝑚 and 𝑎 represent the stoichiometric coefficients of the ions. We can use this equilibrium reaction to write the solubility product equation. The K sp equals the concentrations of the ions multiplied together. We show them in brackets to represent their concentrations. Often, the unit that is used to measure concentration is moles per liter. These concentrations are raised to the power of their coefficients.

Let’s apply this to vanadium(III) carbonate. We are given the chemical formula for vanadium(III) carbonate, which is V2(CO3)3, which we can write as a single solid reactant. The Roman numeral III in the vanadium(III) ion name indicates that this cation has a three-plus charge state. The carbonate anion has a two-minus charge. From the chemical formula of the compound, we can see that for each equivalent of reactant dissolved, there are two vanadium(III) ions produced. And for every two vanadium(III) ions present, there are three carbonate ions in solution.

Now that we have written the balanced equilibrium reaction for the dissolution of vanadium(III) carbonate, we can write the equation for the solubility product. First, we write vanadium(III) and carbonate ions multiplied by one another. We write them in brackets to indicate their concentrations. Then, we raise the concentration of each ion to their stoichiometric coefficient.

Therefore, the equation for the solubility product of vanadium(III) carbonate, V2(CO3)3, is K sp equals the concentration of V3+ raised to the second power times concentration of CO32− raised to the third power.

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