Question Video: Finding the Maximum Height Attained by an Object Projected Vertically Upwards | Nagwa Question Video: Finding the Maximum Height Attained by an Object Projected Vertically Upwards | Nagwa

Question Video: Finding the Maximum Height Attained by an Object Projected Vertically Upwards Mathematics • Second Year of Secondary School

A particle is projected vertically upward at 7 m/s from a point 38.7 m above the ground. Find the maximum height the particle can reach from the ground. Consider the acceleration due to gravity to be 9.8 m/s².

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Video Transcript

A particle is projected vertically upward at seven meters per second from a point 38.7 meters above the ground. Find the maximum height the particle can reach from the ground. Consider the acceleration due to gravity to be 9.8 meters per second squared.

Let’s begin by sketching a diagram modeling the situation. We are told that a particle is projected vertically upwards at seven meters per second. We will call this initial velocity 𝑢. The point at which the particle is projected from is 38.7 meters above the ground. And we are asked to find the maximum height the particle can reach from the ground. We know that at this maximum height, the velocity of the particle will be equal to zero. Finally, we are told that the acceleration due to gravity is equal to 9.8 meters per second squared, and we know that this will act vertically downwards.

In order to find the height ℎ, we will begin by finding the displacement of the particle from its initial position to its maximum height. We will call this displacement 𝑠 meters.

We can do this using the equations of motion or SUVAT equations. If we let the positive direction be vertically upwards, we have 𝑢 is equal to seven meters per second and 𝑣 is equal to zero meters per second. Since gravity is acting in the negative direction, 𝑎 is equal to negative 9.8 meters per second squared. We are trying to calculate the displacement 𝑠. We will use the equation 𝑣 squared is equal to 𝑢 squared plus two 𝑎𝑠.

Substituting in our values, we have zero squared is equal to seven squared plus two multiplied by negative 9.8 multiplied by 𝑠. This simplifies to zero is equal to 49 minus 19.6𝑠. We can then add 19.6𝑠 to both sides. And dividing through by 19.6, 𝑠 is equal to 2.5. The displacement of the particle to reach its maximum height is 2.5 meters. And we can therefore conclude that the particle travels 2.5 meters vertically upwards.

The height above the ground at this point will therefore be equal to 38.7 meters plus 2.5 meters. 38.7 plus 2.5 is equal to 41.2. And we can therefore conclude that the maximum height the particle can reach from the ground is 41.2 meters.

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