Video: Finding the Power of a Particle Moving under a Force in the Vector Form Using a Position-Time Expression

A particle of unit mass is moving under the action of a force 𝐅 = βˆ’2𝐒 + 4𝐣. Its displacement, as a function of time, is given by 𝐒(𝑑) = 2𝑑𝐒 + (7𝑑² + 2𝑑)𝐣. Find the value of d/d𝑑 (𝐅 β‹… 𝐒) when 𝑑 = 4.

01:55

Video Transcript

A particle of unit mass is moving under the action of a force 𝐅, which is equal to negative two 𝐒 plus four 𝐣. Its displacement as a function of time is given by 𝐒 of 𝑑 equals two 𝑑𝐒 plus seven 𝑑 squared plus two 𝑑𝐣. Find the value of the derivative of the dot product of 𝐅 and 𝐒 with respect to 𝑑 when 𝑑 is equal to four.

In this question, we’ve been given two vectors. One describes the force and one describes the displacement of the particle. We’re asked to find the derivative of the dot product of these with respect to time. So let’s just begin by finding the dot product of 𝐅 and 𝐒. To achieve this, we multiply the components for 𝐒. So that’s negative two times two 𝑑. And then we add the products of the 𝐣 components. So that’s four times seven 𝑑 squared plus two 𝑑. We distribute our parentheses and simplify it. And we find that the dot product of 𝐅 and 𝐒 is negative four 𝑑 plus 28𝑑 squared plus eight 𝑑. Now in this question, we’re looking to find the derivative of this expression with respect to time. These are simple power terms. So we can differentiate term by term.

The derivative of negative four 𝑑 with respect to 𝑑 is negative four. When we differentiate 28𝑑 squared, we multiply the entire term by the exponent and then reduce the exponent by one. So that’s two times 28𝑑, which is 56𝑑. Then the derivative of eight 𝑑 is eight. And so we simplify it, and we find that the derivative of the dot product of 𝐅 and 𝐒 with respect to 𝑑 is four plus 56𝑑. We’re told to evaluate this when 𝑑 is equal to four. So that’s four plus 56 times four which is equal to 228. Now actually, what we’ve calculated is the power. The dot product of 𝐅 and 𝐒 is the work. Then when we differentiate the work with respect to time, we get the power. And so we can say that this will be measured in power units. The derivative of the dot product of 𝐅 and 𝐒 with respect to 𝑑 when 𝑑 equals four is 228 power units.

Nagwa uses cookies to ensure you get the best experience on our website. Learn more about our Privacy Policy.